Question
In: Statistics and Probability
A sample of participants has embarked on a weight loss journey. At the end of the...
A sample of participants has embarked on a weight loss journey. At the end of the three-month period, the number of pounds lost was measured. In addition, each participant was given a self-esteem measure.
|
LBS LOST |
SELF-ESTEEM |
|
2 |
12 |
|
5 |
15 |
|
5 |
15 |
|
4 |
14 |
|
2 |
14 |
|
3 |
16 |
|
6 |
19 |
|
4 |
19 |
|
3 |
15 |
|
5 |
16 |
|
5 |
15 |
Compute the correlation for this data
SSx =
SSy =
Σ XY=
SP=
r=
Coefficient of determination=
Solutions
Expert Solution
| LBS LOST(X) | SELF-ESTEEM(Y) | Mx | My | X-Mx | Y-My | (X-Mx)^2 | (Y-My)^2 | (X-Mx)(Y-My) | XY | |
| 2 | 12 | 4 | 15.45455 | -2 | -3.45455 | 4 | 11.9339157 | 6.9091 | 24 | |
| 5 | 15 | 4 | 15.45455 | 1 | -0.45455 | 1 | 0.206615702 | -0.45455 | 75 | |
| 5 | 15 | 4 | 15.45455 | 1 | -0.45455 | 1 | 0.206615702 | -0.45455 | 75 | |
| 4 | 14 | 4 | 15.45455 | 0 | -1.45455 | 0 | 2.115715703 | 0 | 56 | |
| 2 | 14 | 4 | 15.45455 | -2 | -1.45455 | 4 | 2.115715703 | 2.9091 | 28 | |
| 3 | 16 | 4 | 15.45455 | -1 | 0.54545 | 1 | 0.297515703 | -0.54545 | 48 | |
| 6 | 19 | 4 | 15.45455 | 2 | 3.54545 | 4 | 12.5702157 | 7.0909 | 114 | |
| 4 | 19 | 4 | 15.45455 | 0 | 3.54545 | 0 | 12.5702157 | 0 | 76 | |
| 3 | 15 | 4 | 15.45455 | -1 | -0.45455 | 1 | 0.206615702 | 0.45455 | 45 | |
| 5 | 16 | 4 | 15.45455 | 1 | 0.54545 | 1 | 0.297515703 | 0.54545 | 80 | |
| 5 | 15 | 4 | 15.45455 | 1 | -0.45455 | 1 | 0.206615702 | -0.45455 | 75 | |
| MEAN | 4 | 15.455 | SSx=18 | SSy=42.72727273 | SP=16 | 696 | ||||
| r=SP/sqrt(SSx*Ssy) | ||||||||||
| r=16/sqrt(18*42.72727273) | ||||||||||
| r=0.5769407 | ||||||||||
SSx=18
SSy=42.72727273
SP=16
XY= 696
r=0.5769407
Coefficient of determination=r sq=r*r=0.5769407*0.5769407= 0.3328606
orchestra answered 2 years agoRelated Solutions
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