In: Statistics and Probability
A nonprofit organization sent mailing labels along with a request for donations to a random sample of 75,000 potential donors on their mailing list and received 5625 donations from the effort. In the past, the organization has had a contribution rate of 6%, but the director of the program hoped that the addition of the mailing labels would increase that rate. Perform a hypothesis test using α=0.05. Be sure to include the following:
The null and alternative hypotheses in symbols and words are as follows:
Ho: p ≤ 0.06 (There has been no change in the contribution rate due to addition of the mailing labels)
H1: p > 0.06 (The addition of the mailing labels has increased the contribution rate)
Test Statistics
The z-statistic is computed as follows:
Test statistic z = 17.297
P-value
P-value corresponding to z = 17.297 for a two tailed test is obtained using standard normal table.
p-value = 0.0000
90% Confidence Interval Calculation
Conclusion
Since p-value = 0.0000 < α = 0.05, we reject null hypothesis Ho.
At 0.05 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.
Since the 90% confidence interval (0.073, 0.077) does not contain the hypothesized value 0.06, the result is significant and we reject null hypothesis.
In other words, at 0.10 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.