Question

In: Statistics and Probability

A survey described the results of a poll of working adults in Canada. Each person in...

A survey described the results of a poll of working adults in Canada. Each person in a random sample was classified according to gender and the number of vacation days he or she usually took each year. The resulting data are summarized in the given table.

Days of Vacation Gender
Male Female
None 51 42
1-5 21 25
6-10 67 79
11-15 108 96
16-20 71 70
21-25 82 58
More than 25 118 79

(a) Is it reasonable to conclude that there is an association between gender and the number of vacation days taken?

Test the appropriate hypotheses using a 0.05 significance level. Calculate the test statistic. (Round your answer to two decimal places.)
χ2 =  

P-value interval

p < 0.001

0.001 ≤ p < 0.01  

  0.01 ≤ p < 0.05

0.05 ≤ p < 0.10

p ≥ 0.10


There is  ---Select--- enough evidence, not enough evidence to conclude that there is an association between gender and the number of vacation days taken.

(b) To what population would it be reasonable to generalize this conclusion?

all working adults

all adults    

only male working adults

only female working adults

working adults in Canada

Solutions

Expert Solution

a)

Chi square test of independence is used to test the association between gender and number of vacation.

The Chi-Square Value is obtained using the formula

Where, the observed values are,

Days of Vacation Gender
Male Female Total
None 51 42 93
1--5 21 25 46
6--10 67 79 146
11--15 108 96 204
16--20 71 70 141
21--25 82 58 140
More than 25 118 79 197
Total 518 449 967

and the expected values are obtained using the formula,

Days of Vacation Gender
Male Female Total
None      93
1--5 24.64 21.36 46
6--10 78.21 67.79 146
11--15 109.28 94.72 204
16--20 75.53 65.47 141
21--25 74.99 65.01 140
More than 25 105.53 91.47 197
Total 518 449 967

Now, the chi-square value is obtained as follow,

Observed,

Expected,

  

51 49.82 1.18 1.40 0.03
21 24.64 -3.64 13.26 0.54
67 78.21 -11.21 125.64 1.61
108 109.28 -1.28 1.63 0.01
71 75.53 -4.53 20.53 0.27
82 74.99 7.01 49.07 0.65
118 105.53 12.47 155.54 1.47
42 43.18 -1.18 1.40 0.03
25 21.36 3.64 13.26 0.62
79 67.79 11.21 125.64 1.85
96 94.72 1.28 1.63 0.02
70 65.47 4.53 20.53 0.31
58 65.01 -7.01 49.07 0.75
79 91.47 -12.47 155.54 1.70
Sum 9.88

The P-value is obtained from ch square distribution table for degree of freedom = (r-1)(c-1) = (7-1)(2-1)=6

Since the P-value is greater than 0.05 at 5% significance level, the null hypothesis is not rejected.

There is not enough evidence to conclude that there is an association between gender and the number of vacation days taken

b)

(b)

Answer: working adults in Canada

Explanation: Since the hypothesis test is performed for working professional of Canada, hence only population of Canada would be reasonable to generalize this conclusion


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