3. An 8 kg stone rests on a vertical spring of force constant 785 N /...

3. An 8 kg stone rests on a vertical spring of force constant 785 N / m. The stone is pushed down about 30 cm and released. (a) Obtain the elastic potential energy of the compressed spring just before releasing it (b) Obtain the maximum height reached by the stone (c) Obtain the velocity just after it leaves the spring.

Solutions

Expert Solution

The elastic potential energy of the spring is given as

U = ½kx² , k is spring constant and x is spring compression.

Maximum hight the stone can reach is

h =U/mg

genius_generous answered 1 year ago

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