In: Statistics and Probability
Having done poorly on their Math final exams in June, six students repeat the course in summer school and take another exam in August. If these students are representative of all students who might attend this summer school in other years, do these results provide evidence that the program is worthwhile? Use a = 0.05. Assume all conditions and assumptions have been satisfied.
Student June August
A 52 49
B 52 68
C 68 74
D 70 66
E 65 73
F 64 75
Calculate the test statistic.
t = _ ? (Round to three decimal places as needed.)
Calculate the P-value
P-value = _ ? (Rounding to four decimal places.)
: Mean difference between the scores in june and scores in the august (June - August)
If the program is worthwhile; August scores > June scores i.e < 0
Null hypothesis : Ho : = 0
Alternate hypothesis : H1: < 0
Left tailed test;
Sample size : Number students repeted the test = 6
d: difference in the scores (June score - August score)
Sample mean difference
Sample standard deviation of the difference : sd
Student | June | August | d | (d-) | (d-)2 |
A | 52 | 49 | 3 | 8.6667 | 75.1111 |
B | 52 | 68 | -16 | -10.3333 | 106.7778 |
C | 68 | 74 | -6 | -0.3333 | 0.1111 |
D | 70 | 66 | 4 | 9.6667 | 93.4444 |
E | 65 | 73 | -8 | -2.3333 | 5.4444 |
F | 64 | 75 | -11 | -5.3333 | 28.4444 |
=-34 | (d-)2=309.3333 | ||||
= -5.6667 |
Test Statistic = -1.765
For left tailed test :
Degrees of freedom = n-1 =6-1 =5
For 5 degrees of freedom, P(t<-1.7647)=0.0689
P-value = 0.0689
As P-Value i.e. is greater than Level of significance i.e
(P-value:0.0689 > 0.05:Level of significance); Fail to Reject
Null Hypothesis
There is not sufficient evidence to conclude that < 0
i.e
There is not sufficient evidence to conclude that the program is worthwhile