In: Statistics and Probability
Professor Jennings claims that only 35% of the students at Flora
College work while attending school. Dean Renata thinks that the
professor has underestimated the number of students with part-time
or full-time jobs. A random sample of 80 students shows that 38
have jobs. Do the data indicate that more than 35% of the students
have jobs? Use a 5% level of significance.
What are we testing in this problem?
single proportionsingle mean
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: p = 0.35; H1: p > 0.35H0: μ = 0.35; H1: μ ≠ 0.35 H0: μ = 0.35; H1: μ > 0.35H0: p = 0.35; H1: p ≠ 0.35H0: p = 0.35; H1: p < 0.35H0: μ = 0.35; H1: μ < 0.35
(b) What sampling distribution will you use? What assumptions are
you making?
The Student's t, since np < 5 and nq < 5.The standard normal, since np > 5 and nq > 5. The standard normal, since np < 5 and nq < 5.The Student's t, since np > 5 and nq > 5.
What is the value of the sample test statistic? (Round your answer
to two decimal places.)
(c) Find (or estimate) the P-value.
P-value > 0.2500.125 < P-value < 0.250 0.050 < P-value < 0.1250.025 < P-value < 0.0500.005 < P-value < 0.025P-value < 0.005
Sketch the sampling distribution and show the area corresponding to
the P-value.
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis? Are the data statistically
significant at level α?
At the α = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant.At the α = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant.At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
(e) Interpret your conclusion in the context of the
application.
There is sufficient evidence at the 0.05 level to conclude that more than 35% of the students have jobs.There is insufficient evidence at the 0.05 level to conclude that more than 35% of the students have jobs.
Solution:
Statistics and Probability
claim : only 35% of the students at Flora College work while attending school.
n = 80 , x = 38 have jobs.
Do the data indicate that more than 35% of the students have jobs?
level of significance = α = 5%
p^ = x/n = 38/80 = 0.475
What are we testing in this problem?
single proportion
(a) What is the level of significance?
level of significance = α = 5% = 0.05
State the null and alternate hypotheses.
H0: p = 0.35; H1: p > 0.35
(b) What sampling distribution will you use? What assumptions are
you making?
The standard normal, since np > 5 and nq > 5.
What is the value of the sample test statistic? (Round your answer
to two decimal places.)
Test statistic = (p^ - p)/√(pq/n) = (0.475-0.35)/√((0.35*0.65)/80)
= 2.34
Test statistic = 2.34
c) Find (or estimate) the P-value.
0.005 < P-value < 0.025
Sketch the sampling distribution and show the area corresponding to
the P-value.
(d) Based on your answers in parts (a) to (c), will you reject
or fail to reject the null hypothesis? Are the data statistically
significant at level α?
At the α = 0.05 level, we reject the null
hypothesis and conclude the data are statistically
significant.
(e) Interpret your conclusion in the context of the
application.
There is sufficient evidence at the 0.05 level to conclude that more than 35% of the students have jobs.