The average size of 8 farms in Indiana County, Pennsylvania,
is 191 acres with standard deviation...
The average size of 8 farms in Indiana County, Pennsylvania,
is 191 acres with standard deviation of 38 acres. The average size
of 10 farms in Greene County, Pennsylvania, is 199 acres with
standard deviation of 12 acres. Can it be concluded that average
size of the farms in Indiana County and the average size of the
farms in Greene County are different? Use 95% confidence interval
to compare
Solutions
Expert Solution
Confidence interval calculation.
Here we can't conclude both countries farms average is different
because the confidence interval contains zero so, there is chance
that both counties farms average may equal.
If Indiana County, Pennsylvania, coal with M = 3% and A = 8.5%
is burned with 10% excess air, calculate the actual air fuel ratio
and the ideal Orsat analysis (no CO and no unburned carbon). Also,
determine the theoretical Orsat analysis if the HHV of the refuse
is 5500 kJ/kg and the % CO in the dry flue gas is 0.2% of the dry
flue gas.
The average age for licensed drivers in a county is 42.6, with a
standard deviation of 12, and the distribution is approximately
normal. A county police officer was interested in whether the
average age of those receiving speeding tickets is less that the
average age of the population who has a license. She obtained a
sample of 16 drivers with speeding tickets. The average age for
this sample was 34.4. Do all the steps of hypothesis testing using
the 0.01...
the
average income in jefferson county is $32,000 with standard
deviation of $12000. what is the probability that a randomly
selected person makes under $30,000?
Park Acreage A state executive claims that the average number of
acres in western Pennsylvania state parks is less than 2000 acres.
A random sample of 12 parks is selected, and the number of acres is
shown. 2075 2065 2174 1934 2265 1936 2277 1968 2183 2029 1976
2151
a. At = 0.01, is there enough evidence to support the claim? Use
the P-value method
b. Find the 99% confidence interval of the true mean.
The average number of acres burned by fires in New Mexico County
is assumed to be normally distributed with a mean of 9000 and a
standard deviation of 695 acres. You are told that the probability
of the number of acres burned between 9350-R and 9350+R is .7802.
Find R. (Hint: Draw a picture to see the area
along with the given probability. Can Goal-Seek or trial and error
help you find the value of R?)
How would I solve...
Assume that the average size for chicken eggs is 49.6 gram with
a standard deviation of 7.5 grams. Assume that the egg sizes are
normally distributed. a. What is the probability that you will have
a size of at least 67.5 gram? b. What is the probability that the
average weight of 15 eggs will be between 46 and 51 grams? c. If we
call an egg “Peewee” size when it is among the smallest 2 percent
of the weight,...
Suppose the average return on Asset A is 6 percent and the
standard deviation is 8 percent, and the average return and
standard deviation on Asset B are 3.2 percent and 2.6 percent,
respectively. Further assume that the returns are normally
distributed. Use the NORMDIST function in Excel® to answer the
following questions.
a. What is the probability that in any given year, the return on
Asset A will be greater than 9 percent? Less than 0 percent?
b. What...
In 1940 the average size of a U.S. farm was 174 acres†. Let's
say that the standard deviation was 56 acres. Suppose we randomly
survey 46 farmers from 1940.
Part (c)
Give the distribution of
X.
(Round your standard deviation to two decimal places.)
X
~
,
Part (d)
The middle 50% of the distribution for X,
the bounds of which form the distance represented by the IQR, lies
between what two values? (Round your answers to two decimal
places.)...
4. Suppose that your customer’s average order size is 50
units with a standard deviation of 11 units . From this large data
set, select a sample size , n=24 and compute the sample average
.
Find the probability that this sample average will be
less than 52.
Find the probability that this sample average will be
between 49 and 53
Find the probability that this sample average will be
greater than 48.
The National Association for Gardening says that the average
vegetable garden size has a standard deviation of 247 sq ft. A
random sample of 210 households shows an average size of 642 sq ft.
Find a 90% confidence interval for the average size vegetable
garden.