In: Statistics and Probability
Two samples are taken with the following numbers of successes
and sample sizes
r1r1 = 24 r2r2 = 28
n1n1 = 70 n2n2 = 89
Find a 97% confidence interval, round answers to the nearest
thousandth.
x1 = | 24 | x2 = | 28 |
p̂1=x1/n1 = | 24/70=0.3429 | p̂2=x2/n2 = | 28/89=0.3146 |
n1 = | 70 | n2 = | 89 |
estimated difference in proportion =p̂1-p̂2 = | 0.0283 | ||
std error Se =√(p̂1*(1-p̂1)/n1+p̂2*(1-p̂2)/n2) = | 0.0751 | ||
for 97 % CI value of z= | 2.170 | ||
margin of error E=z*std error = | 0.1630 | ||
lower bound=(p̂1-p̂2)-E= | -0.1347 | ||
Upper bound=(p̂1-p̂2)+E= | 0.1912 | ||
from above 97% confidence interval for difference in population proportion =(-0.135,0.191) |