In: Statistics and Probability
71.
Use the table below to find the probability.
Positive Test Result | Negative Test Result | |
Subject Uses Drugs |
44 (True Positive) |
6 (False Negative) |
Subject is Not a Drug User |
90 (False Positive) |
860 (True Negative) |
A. If 2 of the 1000 test subjects are randomly selected, find the probability that both had false positive results. Assume that the 2 selections are made without replacement. (Round to 4 decimals)
B.
If 3 of the 1000 test subjects are randomly selected, find the probability that all had false negative results. Assume that the 3 selections are made with replacement. (Round to 9 decimals)
74.
Determine whether a probability distribution is given. If a probability distribution is given, find its mean. (Round to the nearest thousandth). If a probability distribution is not given, state (not a probability distribution). (Check your spelling!)
x | P(x) |
0 | 0.658 |
1 | 0.287 |
2 | 0.050 |
3 | 0.004 |
4 | 0.001 |
71.
Positive Test Result | Negative Test Result | Total | |
Subject Uses Drugs | 44 | 6 | 50 |
Subject is not a Drug User | 90 | 860 | 950 |
Total | 134 | 866 | 1000 |
A. There are total 1000 subjects and 90 "False Positive"
Subjects.
So 2 subjects can be chosen from 1000 subjects in-
ways. (by without replacement)
and 2 subjects can be chosen from 90 "False Positive" subjects in -
ways (by without replacement)
The Probability that if 2 subjects are randomly chosen from 1000
subjects. Then the probability that both had false positive
results is:
B. There are total 1000 subjects and 6 "False Negative" Subjects.
So 3 subjects can be chosen from 1000 subjects in-
ways. (by with replacement)
and 3 subjects can be chosen from 6 "False negative" subjects
in -
ways (by with replacement)
The Probability that if 3 subjects are randomly chosen from 1000
subjects. Then the probability that all had false negative
cases is:
74. Determination whether the following the
given probability distribution or not:
The given distribution is:
x | p(x) |
0 | 0.658 |
1 | 0.287 |
2 | 0.050 |
3 | 0.004 |
4 | 0.001 |
To determine whether this distribution is probability distribution
or not we've to check whether-
So as we can see that here all
are between 0 to 1, so first condition satisfied.
and
We can say that the given distribution is probability distribution.
Mean=E(X)=
=0.403
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