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Two shuffleboard disks of equal mass, one orange and the othergreen, are involved in a...

Two shuffleboard disks of equal mass, one orange and the other green, are involved in a perfectly elastic glancing collision. The green disk is initially at rest and is struck by the orange disk moving initially to the right at vOi = 4.95 m/s as in Figure a, shown below. After the collision, the orange disk moves in a direction that makes an angle of θ = 39.0° with the horizontal axis while the green disk makes an angle of ϕ = 51.0° with this axis as in Figure b. Determine the speed of each disk after the collision

vof =_________ m/s

vgf =__________ m/s

Solutions

Expert Solution

Using law of conservation of momentum,

(m x 4.95) = (m x v1f cos(39)) + (m v2f cos(51))

4.95 = 0.78 v1f + 0.63 v2f ...... (1)

In y-direction

V2f sin(51) = v1f sin(39)

V2f = 0.8097 v1f

Putting in equation (1)

4.95 = 0.78 v1f + (0.63 x 0.8097 v1f)

V1f = 3.84 m/s

V2f = 0.8097 x 3.84 = 3.11 m/s

genius_generous answered 2 years ago
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