5. For the titration of 50.00 mL of 0.0500 M Ce4+ with 0.1000 M Fe2+ in...

5. For the titration of 50.00 mL of 0.0500 M Ce4+ with 0.1000 M Fe2+ in the presence of 1 M H2SO4, please calculate the system potential while 3.00 mL of Fe2+ is added.

Ce4+ + e <==> Ce3+, E0 = + 1.44 V (in 1 M H2SO4)

Fe3+ + e <==> Fe2+, E0 = + 0.68 V (in 1 M H2SO4).

Answer is 1.49 V

5b) In the above titration, what's the electrode potential after 28.90 mL of Fe2+ is added?

Answer is 0.73 V.

Just wondering, how they got that?

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queen_honey_blossom answered 1 year ago

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