Question

In: Math

f (x) = -0.248226*cos (2 x) - 0.0184829*cos ((2+2)x) - 0.0594608*cos(x)*sin(x) + 0.123626*sin ((2+2)x). The intervall...

f (x) = -0.248226*cos (2 x) - 0.0184829*cos ((2+2)x) - 0.0594608*cos(x)*sin(x) + 0.123626*sin ((2+2)x).

The intervall is ]0, 3/2[

What is the local maximum and local minimum? Answer with 5 decimals

Solutions

Expert Solution

We use 2nd derivative test to find local Maxima and minima.

f'(x)= d/dx[-0.248226*cos (2 x) - 0.0184829*cos (2+2x) - 0.0594608*cos(x)*sin(x) + 0.123626*sin ((2+2x)]

Here we write cos(x)*sin(x) = (1/2)sin(2x) = 0.5sin(2x)

Therefor, 0.0594608*cos(x)*sin(x) = 0.0297304 sin(2x)

Here we get,

milcah answered 2 years ago
Next > < Previous

Related Solutions

For the given function determine the following: f (x) = (sin x + cos x) 2...
For the given function determine the following: f (x) = (sin x + cos x) 2 ; [−π,π] a) Find the intervals where f(x) is increasing, and decreasing b) Find the intervals where f(x) is concave up, and concave down c) Find the x-coordinate of all inflection points
Consider the function on the interval (0, 2π). f(x) = sin(x)/ 2 + (cos(x))^2 (a) Find...
Consider the function on the interval (0, 2π). f(x) = sin(x)/ 2 + (cos(x))^2 (a) Find the open intervals on which the function is increasing or decreasing. (Enter your answers using interval notation.) increasing decreasing (b) Apply the First Derivative Test to identify the relative extrema. relative maximum (x, y) = relative minimum (x, y) =
S(x) is a cubic spline for the function f(x) = sin(pi x/2) + cos(pi x/2) at...
S(x) is a cubic spline for the function f(x) = sin(pi x/2) + cos(pi x/2) at the nodes x0 = 0 , x1 = 1 , x2 = 2 and satisfies the clamped boundary conditions. Determine the coefficient of x3 in S(x) on [0,1] ans. pi/2 -3/2
Consider the function on the interval (0, 2π). f(x) = sin(x) cos(x) + 2 (a) Find...
Consider the function on the interval (0, 2π). f(x) = sin(x) cos(x) + 2 (a) Find the open interval(s) on which the function is increasing or decreasing. (Enter your answers using interval notation.) increasing     ( )    decreasing     ( )   (b) Apply the First Derivative Test to identify all relative extrema. relative maxima     (x, y) =    (smaller x-value) (x, y) = ( )    (larger x-value) relative minima (x, y) =    (smaller x-value) (x, y) = ​   ...
Find the absolute maximum and absolute minimum values of f(x) = cos(2x)+2 sin(x) in the interval...
Find the absolute maximum and absolute minimum values of f(x) = cos(2x)+2 sin(x) in the interval [0; pi]
a. (5 Marks) 1 1 cos(x)cos(y) = -cos(x-y) + -cos(x + y) 1 l sin(x)sin(y) =...
a. 1 1 cos(x)cos(y) = -cos(x-y) + -cos(x + y) 1 l sin(x)sin(y) = -cos(x-y)--cos(x+ y) 1 l sin(x)cos(y) =—sin(x-y) +-sin(x + y) A DSB-FC (double sideband-full carrier) signal s(t) is given by, s(t) = n cos(2rr/cf)+ cos(2«-/mt)cos(2«-fct) What is the numeric value for the AM index of modulation, m, fors(f) ?
Let F (x, y) = y sin x i – cos x j, where C is...
Let F (x, y) = y sin x i – cos x j, where C is the line segment from (π/2,0) to (π, 1). Then C F•dr is A 1 B 2 C 5/2 D 3 E 7/2
Exercise 4: Find all local extrema for f ? = sin^2 ? + cos ? on...
Exercise 4: Find all local extrema for f ? = sin^2 ? + cos ? on the interval [− ?/ 2 , ?/ 2 ]. Verify your answer by graphing.
f(r,?) f(x,y) r(cos(?)) = x r(cos(2?)) = ? r(cos(3?)) = x3-3xy2/x2+y2 r(cos(4?)) = ? r(cos(5?)) =...
f(r,?) f(x,y) r(cos(?)) = x r(cos(2?)) = ? r(cos(3?)) = x3-3xy2/x2+y2 r(cos(4?)) = ? r(cos(5?)) = ? Please complete this table. I am having trouble converting functions from polar to cartesian in the three dimensional plane. I understand that x=rcos(?) and y=rsin(?) and r2 = x2 + y2 , but I am having trouble understanding how to apply these functions.
Let S={(x,y,z) | x^2+y^2+4z^2=9} be a closed surface in R3. F(x,y,z)=(cos x, sin x, x^2+y^2+z^2) is...
Let S={(x,y,z) | x^2+y^2+4z^2=9} be a closed surface in R3. F(x,y,z)=(cos x, sin x, x^2+y^2+z^2) is a vector field. Compute ∫∫ (▽xF) ds
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT