Question

In order to estimate the proportion of students on a particular campus who favor a campus-wide ban on alcohol, a social researcher interviewed a random sample of 100 students from the college population. She found that 36% of the sample favored banning alcohol. (9 points)

            a) Find the mean of the sampling distribution of proportions (µ_p).

            b) Find the standard error of the proportion (σ_p).

            c) Find the estimated standard error of the proportion (s_p).

Answer 1

Solution:

Given that,

n = 100

= 36% =0.36

1 - = 1 - 0.36 = 0.64

a ) The sampling distribution of proportions = =   = 0.07

b )The standard error of the proportion = = ( 1 - ) / n

=  0.36 * 0.64 / 100

= 0.0480

= 0.0480

c ) The sample standard error of the proportion = SEP= ( 1 - ) / n

=  0.36 * 0.64 / 100

= 0.0480

SEP= 0.0480