In: Statistics and Probability
In a random sample of 1500 US adults, 780 of them are “Thriving” which is defined as rating their current life as 7 or higher on a 10-point scale and rating their future life as 8 or higher on a 10-point scale. Find and interpret a 99% confidence interval for the proportion of all US adults who are thriving (based on this definition.)
We have given here,
x=780
n=1500
Estimate for sample proportion= 0.52
Level of significance is =1-0.99=0.01
Z critical value(using Z table)=2.576
Confidence interval formula is
=(0.4868,0.5532)
Lower limit for confidence interval=0.4868
Upper limit for confidence interval=0.5532
We are 99% confidennt that population proportion of all US adults who are thriving is between 0.4868 to 0.5532 |