A 115 kg seal at an amusement park slides from rest down a ramp into the...

A 115 kg seal at an amusement park slides from rest down a ramp into the pool below. The top of the ramp is 2.00 m higher than the surface of the water and the ramp is inclined at an angle of 26.5 ∘ above the horizontal.

Part A

Part complete

If the seal reaches the water with a speed of 4.55 m/s, what is the work done by kinetic friction?

Express your answer using three significant figures.

Part B

What is the coefficient of kinetic friction between the seal and the ramp?

Solutions

Expert Solution

Given data .

Mass of block m = 115 kg

Inclination angle = 26.5 degrees

Height of ramp h = 2 m

Final velocity vf = 4.55 m/s

a) work energy theorem.

W = 1/2 m(vf^2 - vi^2)+mg(yf -yi)

= 115*0.5 [(4.55^2 -0)]+115*9.8( - 2)

w = -1064 J

Net force along perpendicular to ramp.

sigma fy = N - mgcostheta

N = mg costheta

uk =- w sintheta / mgcostheta*h

= 1064*tan26.5/115*9.8*2

Coefficient of kinetic friction uk = 0.235

genius_generous answered 1 year ago

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