In: Physics
A 115 kg seal at an amusement park slides from rest down a ramp into the pool below. The top of the ramp is 2.00 m higher than the surface of the water and the ramp is inclined at an angle of 26.5 ∘ above the horizontal.
Part A
Part complete
If the seal reaches the water with a speed of 4.55 m/s, what is the work done by kinetic friction?
Express your answer using three significant figures.
Part B
What is the coefficient of kinetic friction between the seal and the ramp?
Given data .
Mass of block m = 115 kg
Inclination angle = 26.5 degrees
Height of ramp h = 2 m
Final velocity vf = 4.55 m/s
a) work energy theorem.
W = 1/2 m(vf^2 - vi^2)+mg(yf -yi)
= 115*0.5 [(4.55^2 -0)]+115*9.8( - 2)
w = -1064 J
Net force along perpendicular to ramp.
sigma fy = N - mgcostheta
N = mg costheta
uk =- w sintheta / mgcostheta*h
= 1064*tan26.5/115*9.8*2
Coefficient of kinetic friction uk = 0.235