Question

There are three different types of tests we learned. What one of the three types is the following? “ A researcher estimates that high school girls miss more days of school than high school boys. A sample of 16 girls showed that they missed an average of 3.9 days of school and a sample of 22 boys showed that they missed an average of 3.6 days. The standard deviation of the 16 girls was .6 and the standard deviation of the boys was .8. Using an alpha level of .01, test the researchers claim.

select the conclusion that should be drawn in step 4. Select one: a. Reject Ho b. Do not reject Ho

The critical value for this problem is: Select one: a. 2.576 b. 2.602 c. 2.947 d. 2.326 e. None of the choices

The degree of freedom for this test where we are assuming that the variances are unequal is: Select one: a. 21 b. 35 c. 16 d. 15 e. 22

The final result from this test is: Select one: a. Evidence supports the claim. b. Evidence does not support the claim

The p-value for this test is: Select one: a. .12 b. .04 c. .01 d. .10 e. .24

The test value to the nearest hundredth is: Select one: a. 1.39 b. 1.32 c. 1.82 d. 2.16 e. None of the choices

Using the problem in question two, the alternate hypothesis for the statistical test would be:

Select one: a. muG < muB (claim) b. muG < muB c. muG > muB (claim) d. muG > muB

Answer 1

A researcher claims that high school girls miss more days of school than high school boys. So it right tailed 2 sample t test.

Null hypothesis, H₀: muG=muB vs. Alternative hypothesis, H₁: muG>muB

where muG=true average days are missed by girls and muB= true average days are missed by boys.

We assume two samples come from two independent normal populations. Now we assume, two populations have unequal variance.

Two-Sample T-Test and CI

Sample N Mean StDev SE Mean
Girls 16 3.900 0.600 0.15
Boys 22 3.600 0.800 0.17

Estimate for difference: 0.300
99% lower bound for difference: -0.254
T-Test of difference = 0 (vs >): T-Value = 1.32 P-Value = 0.098 DF = 35

Since P-value=0.098>0.01 so Option is b. Do not reject Ho.

The degree of freedom for this test where we are assuming that the variances are unequal is: b. 35

The final result from this test is: b. Evidence does not support the claim

The p-value for this test is: d. 0.10.

The test value to the nearest hundredth is: b. 1.32

Using the problem in question two, the alternate hypothesis for the statistical test would be:

c. muG > muB (claim)