Question

A basketball team sells tickets that cost $10, $20 or, for VIP seats, $30. The team has sold 3266 tickets overall. It has sold 238 more $20 tickets than $10 tickets. The total sales are $64,850. How many tickets of each kind have been sold?

Answer 1

Ans.

x = 1025 = Number of tickets sold at $10

y = 1263 = Number of tickets sold at $20

z = 978 = Number of tickets sold at $30

Here,

Assume x = Number of tickets sold at $10

Assume y = Number of tickets sold at $20

Assume z = Number of tickets sold at $30

Now,

A basketball team has sold 3266 tickets overall.

So the equation is: x + y + z = 3266

Here, 238 more $20 tickets than $10 tickets: y = 238 + x

Total Sales = $64850

So the equation is:

Now put value of y = 238 + x in other 2 equations:

1. x + 238 + x + z = 3266

• ----------------------------- 1

1. 

• 
• ----------------------- 2

Now, by solving equation 1 and 2:

x = 1025 , z = 978 & y = 1263