In: Biology
Hardy Weinberg Lab
When you have finished copy and past your answers into the submission box in the Hardy Weinberg Lab assignment.
Equations: p + q = 1 p 2 + 2pq + q2 = 1
1. what is the hardy weinberg symbol for the frequency of the dominant allele? ________
2. what is the hardy weinberg symbol for the frequency of the recessive allele __________
3. what is the hardy weinberg symbol for the frequency of the heterozygous genotype ________
4. what is the hardy weinberg symbol for the frequency of the homozygous dominant genotype _____
5. what is the hardy weinberg symbol for the frequency of the homozygous recessive genotype ______
6. If the allele frequency of "r" is .75 what is the allele frequency of "R" ______________
7. If the allele frequency of "R" is .15, what is the allele frequency of "r" _________________
8. In a population the homozygous dominant individuals make up 81% of the population, heterozygous individuals make up 18% and homozygous recessive, what is the frequency of the "p" allele?
9. Tay-Sachs disease is caused by a recessive allele. The frequency of this allele is 0.1 in a population of 3600.
A. what is the frequency of the dominant allele?
B. How many people in this population will have Tay-Sachs?
C. How many people in this population are Tay-Sachs carriers?
10. If a population is at Hardy Weinberg equilibrium then evolution _______________ happening.
1. p is the hardy weinberg symbol for the frequency of the dominant allele.
According to the given formula p + q = 1. For a population to say it is in Hardy Weingberg Equilibrium p + q = 1. Symbol p represents frequency for the dominant allele.
2. q is the hardy weinberg symbol for the frequency of the recessive allele.
According to the given formula p + q = 1. For a population to say it is in Hardy Weingberg Equilibrium p + q = 1. Symbol q represents frequency for the recessive allele.
3. 2pq is the hardy weinberg symbol for the frequency of the heterozygous genotype.
According to the formula given, + 2pq + = 1. Heterozygous genotype means one recessive allele and one dominant allele. So, symbol 2pq represents the frequency of the heterozygous genotype, where p is frequency of dominant allele and q is frequency of the recessive allele.
4. is the hardy weinberg symbol for the frequency of the homozygous dominant type genotype.
According to the formula given, + 2pq + = 1. Homozygous dominant genotype means RR which means p * p . So, symbol represents the frequency of the homozygous dominant genotype.
5. is the hardy weinberg symbol for the frequency of the homozygous recessive type genotype.
According to the formula given, + 2pq + = 1. Homozygous recessive genotype means rr which means p * p . So, symbol represents the frequency of the homozygous recessive genotype.
6. To say, a population is in Hardy Weingberg Equilibrium the sum of allele frequency of recessive and dominant allele should be equal to 1. So, if the allele frequency of ''r'' is .75, considering r is the recesive allele. Then according to the formula p + q = 1 (p is allele frequency of R and q is allele frequency of r). We have,
p + 0.75 = 1.
p = 1 - 0.75 = 0 .25.
Therefore, the allele frequency of the "R" allele is 0.25.
7. As discussed in the question number 6. p + q =1. Here we are given with allele frequency of "R" that is value of p.
So,
0.15 + q =1
q = 1 - 0.15
q = 0.85.
Therefore, the allele frequency of the "r" allele is 0.85.
8. The frequency of the homozygous recessive genotype represents 1% that is 0.01, the square root of q is 0.1 (10%).
Since q = 0.1 amd p + q - 1. then p = 0.9 (90%), this is the frequency of the dominant allele.
The frequency of heterozygous individuals will be equal to 2pq. In this case, 2pq = 2 * 0.9 * 0.1 = 0.18 (18%). The frequency of individuals heterozygous for this gene is equal to 18%.
Therefore, the frequency of p allele is 0.9.