Question

1. On a course pre-test at a large university, 102 out of 600 randomly selected students taking Accounting II answered every question correctly. At the end of the course, 144 out of 450 randomly selected students answered every question correctly. (The pre and post-tests were identical.)

1. What is considered “success” for the binomial variable being tested?

2. Fill in the blanks to complete the hypotheses for a test to determine if the course instruction was effective in improving students’ knowledge about accounting? (The pre-test population is population #1.)

H₀: p₁ ___ p₂

H₁: p₁ ___ p₂

3. Calculate a 98% confidence interval for the difference in proportions of success. Write a sentence reporting your confidence interval as percentage point differences rounded to the nearest tenth of a percent.

4. Based on the confidence interval, was the course instruction effective in improving students’ knowledge about accounting? Why or why not?

Answer 1

a) What is considered “success” for the binomial variable being tested?

Success is Student answered the very question correctly.

The hypotheses for a test to determine if the course instruction was effective in improving students’ knowledge about accounting?(The pre-test population is population 1 )

Sample 1: pre-test population

Sample 2: post-test population

we want to find that it is effective or not.

i.e. P1 < P2

Ho: P1 = P2  

vs

Ha:- P1 < P2

a) The 98 % confidence interval is

c,d)

Based on the confidence interval, was the course instruction effective in improving students’ knowledge about accounting? Why or why not?

Here confidence interval for P1-P2 is ( -0.212,-0.088)

Here Upper confidence interval is < 0.

So here we can say that the P1-P2 < 0.

So we can say that the course instruction is effective in improving students’ knowledge about accounting.