Question

determine the total mass gain or loss for the reaction by comparing your initial mass to your final mass. combined mass of vinegar and baking soda.
initial total mass?
final total mass?
difference?
run 1 grams of sodium bicarbonate 1.4
molar mass 84.006
number of moles 0.016665
0.92g acetic acid 
molar mass 60
number of moles 0.0154
what is the formula?
please tell me initial total mass, final mass and the difference between the two

Answer 1

Baking soda and vinegar react with each other because of an acid-base reaction.

Baking soda is a bicarbonate (NaHCO₃) and vinegar is an acetic acid (CH₃COOH). One of the products this reaction creates is carbon dioxide.

The first reaction is this:

CH₃COOH + NaHCO₃ CH₃COONa + H₂CO₃

It would form Sodium Acetate and Carbonic Acid. The Carbonic Acid will then break down into Carbon Dioxide and Water:

H₂CO₃ = H₂O + CO₂

Making the overall equation

CH₃COOH + NaHCO₃ CH₃COONa + CO₂ + H₂O
0.92 g 1.4 g
0.0154 mol 0.0167 mol

In the above reaction equation,

1 mol of CH₃COOH reacts with 1 mol of NaHCO₃ produces 1 mol of CH₃COONa, 1mol of CO₂ and 1 mol of H₂O.

0.0154 mol of CH₃COOH reacts with 0.0154 mol of NaHCO₃ .

So, excess moles of NaHCO₃ left after reaction =  0.0167 mol - 0.0154 mol

= 0.0013 mol

Molar mass of NaHCO₃ = 84.006 g/mol

So, 1 mole of NaHCO₃ = 84.006 g

0.0013 mole of NaHCO₃ = 0.0013 x 84.006 g = 0.109 g

Additional part:

1 mol of CH₃COOH reacts with 1 mol of NaHCO₃ produces 1 mol of CH₃COONa, 1mol of CO₂ and 1 mol of H₂O.

0.0154 mol of CH₃COOH produces 0.0154 mol of each product.

Molar mass of CH₃COONa = 82 g/mol

So, 1 mole of NaHCO₃ = 82 g

0.0154 mole of NaHCO₃ = 0.0154 x 82 g = 1.2628 g