In: Statistics and Probability
Non-Smokers (0) |
Smokers (1) |
Overall |
|
Sample size |
254 |
72 |
326 |
Min |
1587.573 |
1927.768 |
1587.573 |
Q1 |
3090.10 |
2863.30 |
3005.05 |
Median |
3430.29 |
3203.50 |
3373.59 |
Q3 |
3742.14 |
3572.04 |
3685.44 |
Max |
4649.322 |
4507.574 |
4649.322 |
Mean |
3398.483 |
3190.109 |
3352.462 |
Standard Deviation |
515.529 |
521.850 |
523.335 |
Compare the five-number summaries between the two subsamples. Briefly comment on what the summaries reveal about the location, dispersion and skewness of the birth weight distributions in the two subsamples. [2 marks]
It is well-known that, on average, smoking by the mother during
pregnancy lowers the birth weight of the child. To investigate this
claim statistically, you will use a hypothesis test.
Set up the null and alternative hypotheses. Make sure to define your notation clearly. [2 marks]
Verify that the Central Limit Theorem applies. Carry out the hypothesis test using the appropriate methodology, show your steps and state your conclusion. [2 marks]
Does it follow from the hypothesis test that children have lower birth weights because their mothers smoking during pregnancy? Explain. [2 marks]
(1)
(i) The mean birth weight of the child of smoking by the mother during pregnancy = 3190.109 is less than the mean birth weight of the child of non - smoking by the mother during pregnancy = 3398.483.
(ii) The variation of birth weight of the child of smoking by the mother during pregnancy = 521.850 is more than the variation of birth weight of the child of non - smoking by the mother during pregnancy = 515.529 .
(iii)
Coefficient of skewness of the distribution of birth weight of the child of smoking by the mother during pregnancy
= 3 X (Mean - Median)/ SD
= 3 X (3190.109 - 3203.50)/ 521.850
= - 0.0770
Coefficient of skewness of the distribution of birth weight of the child of non - smoking by the mother during pregnancy
= 3 X (Mean - Median)/ SD
= 3 X (3398.483 - 3430.29)/ 515.529
= - 0.1851
The distribution of birth weight of the child of smoking by the mother during pregnancy is less negatively skewed = - 0.0770 than the distribution of birth weight of the child of non - smoking by the mother during pregnancy
= - 0.1851
(2)
(i)
H0: Null Hypothesis: ( On average, smoking by the mother during pregnancy does not lower the birth weight of the child. )
HA: Alternative Hypothesis: ( On average, smoking by the mother during pregnancy lowers the birth weight of the child. ) (Claim)
(ii)
Given:
n1 = 254
n2 = 72
1 = 3398.483
2 = 3190.109
s1 = 515.529
s2 = 521.850
Pooled Standard Deviation is given by:
Test Statistic is given by:
Take
= 0.05
df = 254 + 72 - 2 = 324
From Table, critical value of t = 1.65
Since calculated value of t = 3.019 is greater than critical value of t = 1.65, the difference is significant. Reject null hypothesis.
Conclusion:
The data support the claim that on average, smoking by the mother
during pregnancy lowers the birth weight of the child.
(iii)
It follows from the hypothesis test that children have lower birth weights because their mothers smoking during pregnancy.
Explanation:
As per the conclusion of the hypothesis test: The data support the
claim that on average, smoking by the mother during pregnancy
lowers the birth weight of the child.