Question

In: Chemistry

A solution is made by mixing exactly 500 mL of 0.149 M NaOH with exactly 500...

A solution is made by mixing exactly 500 mL of 0.149 M NaOH with exactly 500 mL of 0.100 M CH3COOH. Calculate the equilibrium concentration of the species below. Ka of CH3COOH is 1.8 X 10-5

[H+], [OH-], [CH3COOH], [Na+], [CH3COO-} enter answer in scientific notation.

Solutions

Expert Solution

[H+] = Kw  / [OH-] = 1.0E-14 / 0.0245 = 4.08E-13 M

[ Na+ ] = 0.0245 + 0.0500 = 0.075 M

[CH3COOH] = 0 M

[CH3COO- ] = 0.05 mol / 1.0 L = 0.0500 M


Related Solutions

A solution is made by mixing exactly 500 mL of 0.153 M NaOH with exactly 500...
A solution is made by mixing exactly 500 mL of 0.153 M NaOH with exactly 500 mL of 0.100 MCH3COOH. Calculate the equilibrium concentration of the species below. Ka of CH3COOH is 1.8 ×10−5 [H+]=? M [OH-]=? M [CH3COOH]=? M [Na+]=? M [CH3COO−]=? M
A solution is made by mixing exactly 500.0 mL of 0.167 M NaOH with exactly 500.0...
A solution is made by mixing exactly 500.0 mL of 0.167 M NaOH with exactly 500.0 mL of 0.100 M CH3COOH. Calculate the equilibrium concentrations of H3O+, CH3COOH, CH3COO-, OH-, and Na+. [H3O+] = M [CH3COOH] =    M [CH3COO-] =    M [OH-] = M [Na+] = M
Be sure to answer all parts. A solution is made by mixing exactly 500 mL of...
Be sure to answer all parts. A solution is made by mixing exactly 500 mL of 0.135 M NaOH with exactly 500 mL of 0.100 M CH3COOH. Calculate the equilibrium concentration of the species below. Ka of CH3COOH is 1.8 × 10^−5 a.) [H+]   Enter your answer in scientific notation. b.) [OH−] M c.) [CH3COOH]     Enter your answer in scientific notation. d.) [Na+] M e.) [CH3COO−] M
Be sure to answer all parts. A solution is made by mixing exactly 500 mL of...
Be sure to answer all parts. A solution is made by mixing exactly 500 mL of 0.146 M NaOH with exactly 500 mL of 0.100 M CH3COOH. Calculate the equilibrium concentration of the species below. Ka of CH3COOH is 1.8 × 10−5 [H+] M Enter your answer in scientific notation. [OH−] M [CH3COOH] M Enter your answer in scientific notation. [Na+] M [CH3COO−] M
What is the pH of a solution made by mixing 500 mL of 1.00 M HCN...
What is the pH of a solution made by mixing 500 mL of 1.00 M HCN and 1.50 L of 0.250 M NaOH, and then diluting the entire solution to a volume of 3.00 L? (Ka HCN = 4.0 x 10-10) A. 8.92 B. 6.52 C. 9.88 D. 9.27 E. 5.08 To obtain one litre of a solution of pH = 7, you should dissolve in water A. Two mol of HI + two mol of CH3NH2 B. One mol...
350. mL of a NaOH solution was added to 500. mL of 2.50 M HNO2. The...
350. mL of a NaOH solution was added to 500. mL of 2.50 M HNO2. The pH of the mixed solution was 1.75 units greater than that of the original acid solution. Calculate the molarity (in M) of the initial NaOH solution. (Ka of HNO2 is 4.5x10-4)
Calculate the pH of a solution prepared by mixing a) 25.0 mL of 0.512 M NaOH...
Calculate the pH of a solution prepared by mixing a) 25.0 mL of 0.512 M NaOH and 34.0 mL of 0.187 M HCl b) 46.0 mL of 0.235 M KOH and 50.0 mL of 0.420 M HC3H5O2 c) 400 mL of 0.250 M NH3 and 250 mL of 0.120 M HCl
Calculate the pH of a solution prepared by mixing a) 25.0 mL of 0.512 M NaOH...
Calculate the pH of a solution prepared by mixing a) 25.0 mL of 0.512 M NaOH and 34.0 mL of 0.187 M HCl b) 46.0 mL of 0.235 M KOH and 50.0 mL of 0.420 M HC3H5O2 c) 400 mL of 0.250 M NH3 and 250 mL of 0.120 M HCl
  19. The pH of a solution prepared by mixing 50.0 mL of 0.125 M NaOH and...
  19. The pH of a solution prepared by mixing 50.0 mL of 0.125 M NaOH and 40.0 mL of 0.125 M HNO3 is ____    [A] 13.29 [B] 8.11 [C] 11.00 [D] 12.14 [E] 7.00 20. The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is ______ [A] 1.34 [B] 5.78 [C]1.90 [D] 1.14 [E] 7.0 21. Consider the following table for Ksp values Cadmium carbonate CdCO3 5.2...
Exactly 47.0 mL of 0.2 M HNO2 are titrated with a 0.2 M NaOH solution. What...
Exactly 47.0 mL of 0.2 M HNO2 are titrated with a 0.2 M NaOH solution. What is the pH at the equivalence point ?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT