Question

In: Statistics and Probability

A survey of adults was conducted in which the subjects were asked whether they agree that...

A survey of adults was conducted in which the subjects were asked whether they agree that the government should prohibit smoking in public places. In addition, each subject was asked how many people lived in their household. The results are summarized in the following contingency table. Use a 0.1 significance level to test for independence between the two variables.

3 or less

More than 3

Agree

82

70

Disagree

67

75

A) Calculate the Table of Expected Values:

3 or less

More than 3

Agree

["69.22", "71.22", "77.03", "79.03"]           

["74.97", "70.25", "79.05", "77.41"]           

Disagree

["72.96", "79.65", "70.55", "71.97"]           

["67.81", "70.03", "71.55", "76.21"]           

B) Calculate the Chi-Squared test statistic: ["1.346", "0.158", "2.826", "1.968", "1.789"]           

C) Calculate the Critical Value:   ["5.024", "7.879", "2.706", "3.841", "6.635"]           

D) Based on this result, there   ["does", "does not"] appear to be enough evidence to support the claim that the number of people in a household is independent of their view on smoking in public areas.

**NOTE the values in-between " " are possible answer choices


Solutions

Expert Solution

(A)

H0: Null Hypothesis: The variables: whether they agree that the government should prohibit smoking in public places and number of people lived in their household are independent (Claim)

HA: Alternative Hypothesis: The variables: whether they agree that the government should prohibit smoking in public places and number of people lived in their household are dependent

Observed Frequencies:

3 or less More than 3 Total
Agree 82 70 152
Disagree 67 75 142
Total 149 145 294

Expected Frequencies:

3 or less More than 3 Total
Agree 149 X 152/ 294 = 77.034 145 X 152/ 294 = 74.966 152
Disagree 149 X 142/ 294 = 71.966 145 X 142/ 294 = 70.034 142
Total 149 145 294

So, Answer is:

3 or less More than 3
Agree 77.03 74.97
Disagree 71.97 70.03

(B)

The Chi-Squared test statistic is got as follows:

Observed (O) Expected (E) (O - E)2/E
149 77.034 0.320
70 74.966 0.329
67 71.966 0.343
75 70.034 0.352
Total = 1.346

So,

Correct option:

1.346

(C)

= 0.10

df = (2 - 1) X (2 - 1) = 1

From Table, critical value of = 2.706

So,

Correct option:

2.706

(D)

Correct option:

Based on this result, there   does appear to be enough evidence to support the claim that the number of people in a household is independent of their view on smoking in public areas.


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