Question

1. There are issues with correct insurance information on file for patients at hospitals an doctors’ offices, there are 700 reimbursement forms randomly picked and 325 have incorrect information or are missing information.

   Create a 90% Confidence Interval

   		43.3% - 49.5%
   		42.7% - 50.1%
   		41.5% - 51.2%
   		1% - 4,369%

Answer 1

Solution :

Given that,

Point estimate = sample proportion = = x / n = 325/700=0.464

1 -   = 1-0.464=0.536

At 90% confidence level

= 1 - 90%  

= 1 - 0.90 =0.10

/2 = 0.05

Z/2 = Z  0.05 = 1.645 ( Using z table )

Margin of error = E Z/2 *(( * (1 - )) / n)

= 1.645 *((0.464*0.536) /700 )

E = 0.031

A 90% confidence interval is ,

- E < p < + E

0.464-0.031 < p < 0.464+0.031

0.433< p < 0.495

43.3% - 49.5%