Question
In: Nursing
A study looked at acupressure and the sleep quality of psychogeriatric patients. Selected data are as...
A study looked at acupressure and the sleep quality of psychogeriatric patients. Selected data are as follows:
|
Pretest M(SD) |
Posttest M(SD) |
t |
p |
|
|
Sleep latency (min) |
34.93 (4.46) |
30.07 (4.80) |
3.61** |
0.001 |
(Lu, Lin, Chen, Tsang, & Su, 2013, p. 134). What do the data mean? Select all that apply.
Question 2 options:
|
There is a difference in the means (M) and standard deviations (SDs) between the pre- and posttests. |
|
|
The difference between the means is not statistically significant. |
|
|
The p-value indicates the probability of a type II error. |
|
|
The difference between the means is statistically significant. |
|
|
The p-value indicates the probability of a type I error. |
Solutions
Expert Solution
According to the study, there is difference between the mean and standard deviation in both pretest and post test. Since the p value is 0.001 which indicates that the study is statistically significant.
Nightingale answered 2 years agoRelated Solutions
A research study examined the effects of meditation on quality of sleep. Fifty individuals were asked...
A research study examined the effects of meditation on quality
of sleep. Fifty individuals were asked how many nights, on average,
they lost sleep at the beginning of the study. Then all fifty
individuals were placed into a meditation intervention every day
for three months. At the end of the three months, the same fifty
individuals were asked how many sleepless nights they had on
average. The mean difference between the before and after
intervention groups was 5.6 nights, with...
7/ The results of an experiment on the effects of sleep training on sleep quality showed...
7/
The results of an
experiment on the effects of sleep training on sleep quality showed
that participants who received eight sessions of sleep enhancement
training had longer sleep duration and better sleep quality than
participants who did not receive the training. This led the
researchers to conclude that an eight-week sleep enhancement
training program is effective for improving sleep quality.
What advantage of
experimental research does this demonstrate?
Multiple Choice Question
Experimental research helps establish cause and effect
relationships....
Three physicians were selected for a study to evaluate the length of stay for patients undergoing...
Three physicians were selected for a study to evaluate the
length of stay for patients undergoing a major surgical procedure.
All these procedures occurred in the same hospital and were without
complications. Eight records were randomly selected from patients
treated over the past 12 months.
Physician
Time
A
9
A
12
A
10
A
7
A
11
A
13
A
8
A
13
B
10
B
6
B
7
B
10
B
11
B
9
B
9
B
11
C...
The following table was derived from a study of HIV patients, and the data reflect the...
The following table was derived from a study of HIV patients,
and the data reflect the number of subjects classified by their
primary HIV risk factor and gender. Test if there is a relationship
between HIV risk factor and gender using a 5% level of
significance:
Gender
Total
HIV Risk Factor
Male
Female
IV drug user
24
40
64
Homosexual
32
18
50
Other
15
25
40
71
83
154
What type of chi-square test will you use (goodness of...
2. Good sleep or bad sleep? ~ A study was conducted to identify the factors affecting...
2.
Good sleep or bad sleep? ~
A study was conducted to identify the factors affecting quality of
sleep for university students. A survey of 290 students of
different majors aged 17-29 years old revealed that 67.2% of these
students suffered from poor sleep.
a.
Create a 95% confidence interval for the
= the population proportion of university students aged 17-29 years
old who suffer from poor sleep.
Final answer:
( ______________________
, _____________________ )
b.
Determine whether each of...
1) Formulate three nursing diagnoses for patients experiencing a sleep disturbance
1) Formulate three nursing diagnoses for patients
experiencing a sleep disturbance
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a
study about the hours of sleep that college students get. You know
that for all people, the average is about 7 hours. You randomly
select 50 college students and survey them on their sleep habits.
From this sample, the mean number of hours of sleep is found to be
6.2 hours with a standard deviation of 0.86hours. We want to
construct a 95% confidence interval for the mean nightly hours of
sleep...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a
study about the hours of sleep that college students get. You know
that for all people, the average is 7.0 hours with a standard
deviation of 1.3 hours. You randomly select 50 college students and
survey them on their sleep habits. From this sample, the mean
number of hours of sleep is found to be 6.40 hours. Assume the
population standard deviation for college students is the same as
for all people....
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a
study about the hours of sleep that college students get. You know
that for all people, the average is about 7 hours. You randomly
select 45 college students and survey them on their sleep habits.
From this sample, the mean number of hours of sleep is found to be
6.2 hours with a standard deviation of 0.97 hours. We want to
construct a 95% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a
study about the hours of sleep that college students get. You know
that for all people, the average is about 7 hours. You randomly
select 35 college students and survey them on their sleep habits.
From this sample, the mean number of hours of sleep is found to be
6.1 hours with a standard deviation of 0.97 hours. You want to
construct a 99% confidence interval for the mean nightly hours of...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- In C++ Write a function that took in SIZE and array [size] and counted the number...
- . What are the current issues with managing the supply chain? In general, how can blockchain...
- Define what an array index value is in JAVA. Then, write a JAVA program that passes...
- A buffer contains 1.0 mol of CH3CO2H and 1.0 mol of CH3CO2- diluted with water to...
- - A primary sedimentation basin for a municipal waste water treatment plant treats a flow of...
- Hello I'm currently having an error that says "main is not abstract and does not override...
- Give a direct proof of the following theorem, upon which case you can use it for...
ADVERTISEMENT