LI2+ ion (a) Calculate energy (in Joules) of the 2px orbital of the ion (b) Calculate...

LI²⁺ ion

(a) Calculate energy (in Joules) of the 2p_x orbital of the ion

(b) Calculate energy (in Joules) and Wavelength (in nm) of the transition from the 4s orbital to the 2pz orbital of the ion

Solutions

Expert Solution

The energy of the orbital depends on the principal quantum number: So:

Now, calculate the energy difference:

$\lamda=4.8631*10^{-7}m=486.31nm$

Now, the ionization energy is the energy you need to move the electron from its ground state to the infinite.

For Li+2:

queen_honey_blossom answered 1 year ago

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