In: Physics
In an oscillating LC circuit, L = 1.39 mH and C = 4.99 ?F. The maximum charge on the capacitor is 3.98 ?C. Find the maximum current.
Given that
The inducatnce of the inductor (L) =1.39mH
=1.39*10-3H
Capacitance of the capacitor (C) =4.99?F
=4.99*10-6F
The maximum charge on the capacitor (Q) =3.98?C
=3.98*10-6C
We know that
U=(1/2)LI2 =Q2/2C
The maximum curent is
I = Q/?LC
= 3.98*10-6C/?(1.39*10-3H)(4.99*10-6F)
= 47.79*10-3 A