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In: Chemistry

A twelve pack of your favorite beverage (12 fl. oz. cans) is placed in a cooler...

A twelve pack of your favorite beverage (12 fl. oz. cans) is placed in a cooler at 70o F. How much heat must be removed (kJ) to cool the beverages to 37o F?

Solutions

Expert Solution

12 fl. oz. means in the cane volume of soda is 12 fluid ounces.
Density of water  0.9587 oz./fl. oz
1 gallon water 8.34 pounds 
1 gallon= 128 fl. oz. 
1 pound = 16 av. oz.

 8.34 pounds = 8.34*16 av. oz.

128 fl. oz. = 8.34*16 av. oz.

and therefore 

  1 fl. oz. of water weighs 8.34 * 16 / 128 av. oz.

                            = 1.0425 av. oz.

Thus 12 fl. oz. of water weigh 12 * 1.0425 av. oz. = 12.51 av. oz.

1 avoirdupois (av. oz) = 28.35 grams

    12.51 av. oz. = 354.66 grams

Given, Initial temperature = 700F = 21.10C

   Final temperature = 370F = 2.80C

T = 21.10C - 2.80C = 18.30C

Specific heat of beverage = 4.10 J/g•°C

Using, Q = m * C * T

= 354.66 grams * 4.10 J/g•°C * 18.30C (gm and celcius cancel out)

Heat removed (Q) = 26610.14 J = 26.61 KJ

queen_honey_blossom answered 2 years ago
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