In: Statistics and Probability
Given Mean = 100
Standard Deviation = 15
z-score = (X - ) /
Question (a)
proportion of the population that has an IQ higher than 94
We need to find P(X > 94)
z-score = (94 - 100) / 15
= -6/15
= -0.4
P(X < 94) will be the area to the left of z-score -0.4 which can be found out from the below attached negative z-table
P(X < 94) = 0.34458
We know that P(X < 94) + P(X > 94) = 1
So P(X > 94)= 1 - 0.34458
= 0.65542
proportion of the population that has an IQ higher than 94 is 0.65542
Question (b)
proportion of the population that has an IQ between 82 and 88
We need to find P(82 < X < 88)
So we find P(X<82) and P(X<88) and subtract P(X<82) from P(X<88) to get P(82 < X < 88)
P(X<82) is calculated as follows
z-score = (82 - 100) / 15
= -18/15
= -1.2
P(X < 82) will be the area to the left of z-score -1.2 which can be found out from the below attached negative z-table
P(X < 82) = 0.11507
P(X<88) is calculated as follows
z-score = (88 - 100) / 15
= -12/15
= -0.8
P(X < 88) will be the area to the left of z-score -0.8 which can be found out from the below attached negative z-table
P(X < 88) = 0.21186
P(82 < X < 88) = P(X<88) - P(X<82)
= 0.21186 - 0.11507
= 0.09679
proportion of the population that has an IQ between 82 and 88 is 0.09679
Question (c)
The IQ score that seperates the highest scoring 67% from the rest of the population
So we need to find a z-score first that has an area of 0.67 to its left
The z-score is 0.43991 from the online calculator sicne the z-table gives only approximate value rounded to 2 decimal places
z-score = (X - ) /
0.43991 = (X - 100) / 15
X - 100 = 15 * 0.43991
X - 100 = 6.59865
X = 106.59865
So The IQ score of 106.59865 seperates the highest scoring 67% from the rest of the population