In: Statistics and Probability
Using a = 0.05, test if the mean weight change is less than 0 if a sample of size 25 people on the Atkins diet yielded a mean change of -2.1 and a sample std dev of 4.0.
Solution:
Step 1) State H0 and H1:
Since we have to test if the mean weight change is less than 0 , this is left tailed test.
Thus:
Vs
Step 2) Test statistic:
Step 3) Critical value:
df = n - 1 = 25 - 1 = 24
One tail area = level of significance = 0.05
t critical value = -1.711
( its negative , since this is left tailed test)
Step 4) Decision Rule:
Reject null hypothesis H0, if t test statistic value < t critical value = -1.711 , otherwise we fail to reject H0
Since t test statistic value = < t critical value = -1.711 , we reject null hypothesis H0.
Step 5) Conclusion:
At 0.05 level of significance, we have sufficient evidence to conclude that: the mean weight change is less than 0.