Question

Given a 2 Gbps link with TCP applications A, B, and C.

• Application A has 32 TCP connections to a remote web server
• Application B has 4 TCP connection to a mail server
• Application C has 15 TCP connections to a remote web server.

According to TCP "fairness", during times when all connections are transmitting, how much bandwidth should Application C have? (Give answer in Mbps, rounded to one decimal place, without units. So for an answer of 1234,567,890 bps you would enter "1234.6" without the quotes.)

Answer 1

Solution:

Given,

=>Bandwidth = 2 Gbps

=>Application A has connections = 32 connections

=>Application B has connections = 4 connections

=>Application C has connections = 15 connections.

=>TCP does fairness.

Explanation:

Calculating total number of connections:

=>Total number of TCP connections = 32 + 4 + 15

=>Total number of TCP connections = 51 connections

Calculating bandwidth of one TCP connection:

=>Bandwidth of one TCP connection = Total bandwidth/total number of connections

=>Bandwidth of one TCP connection = 2 Gbps/51

=>Assuming 1 Gbps = 1000 Mbps

=>Bandwidth of one TCP connection = 2*1000 Mbps/51

=>Bandwidth of one TCP connection = 39.215 Mbps

Calculating bandwidth for application C:

=>Bandwidth for application C = number of TCP connection for application C*bandwidth of one connection.

=>Bandwidth for application C = 15*39.215 Mbps

=>Bandwidth for application C = 588.235 Mbps

=>Rounding off to one decimal place, bandwidth for application C = 588.2 Mbps

=>Hence answer will be 588.2

I have explained each and every part with the help of statements attached to it.