Question

In: Economics

2) A 30 year $100, 000 loan with i = 9% is to be paid off...

2) A 30 year $100, 000 loan with i = 9% is to be paid off with yearly payments beginning one year after the loan is made. The first 20 payments are K and the last 10 payments are 4K. Find K. Also for the first four full years make an amortization table and explain why for each year principle repaid is negative.

Solutions

Expert Solution

Loan amount = 100,000

Loan duration = 30 years

Interest rate = 9%

Present value of all payment made must be 100,000

Present value of payment made in 1st year [K / (1 + 0.09)^1]

Present value of payment made in 2nd year [K / (1 + 0.09)^2]

.....

Present value of payment made in 21st year [2K / (1 + 0.09)^21]

Present value of payment made in 22nd year [2K / (1 + 0.09)^22]

......

Present value of payment made in 30th year [2K / (1 + 0.09)^30]

Sum of present value of payments: [K / (1 + 0.09)^1] + [K / (1 + 0.09)^2] + ............ + [2K / (1 + 0.09)^30]

I will divide the series in two parts:

First part:

[K / (1 + 0.09)^1] + [K / (1 + 0.09)^2] + .................... + [K / (1 + 0.09)^19] + [K / (1 + 0.09)^20] whose sum can be calculated using G.P. formuls which is [a * (1 - r^n) / (1 - r)]

where a = [K / (1 + 0.09)^1]

r (ratio of two consecutive terms) = 0.9174

n = 20

Sum of first part: [K / (1 + 0.09)^1] * (1 - 0.9174^20) / (1 - 0.9174) = 9.13K

Second part:

[2K / (1 + 0.09)^21] + [2K / (1 + 0.09)^22] + .................... + [2K / (1 + 0.09)^29] + [2K / (1 + 0.09)^30] whose sum can be calculated using G.P. formuls which is [a * (1 - r^n) / (1 - r)]

where a = [2K / (1 + 0.09)^21]

r (ratio of two consecutive terms) = 0.9174

n = 10

Sum of first part: [2K / (1 + 0.09)^21] * (1 - 0.9174^10) / (1 - 0.9174) = 2.29K

Sum of payment made = 9.13K + 2.29K = 11.42K which must be equal to 100,000

Thus, K = 8,757.51

For the first 4 years, interest accrued is more than amount paid which result in negative principal.

Year Pending amount Interest till end of the year Amount paid Interest paid Principal paid Pending balance
1           100,000.00                                  9,000.00         8,757.51         8,038.04             719.47          100,242.49
2           100,242.49                                  9,021.82         8,757.51         7,973.29             784.22          100,506.80
3           100,506.80                                  9,045.61         8,757.51         7,902.71             854.80          100,794.91
4           100,794.91                                  9,071.54         8,757.51         7,825.78             931.73          101,108.94

Related Solutions

A 20 year loan of $120, 000 at i = 6% is paid off by paying...
A 20 year loan of $120, 000 at i = 6% is paid off by paying 130% of each year’s interest at the end of each year for the first 12 years, and then for the next 8 years pay off the loan by paying off constant principle at the end of each year. Find the value of the last payment.
7. Construct a LOAN AMORTIZATION schedule for a 3 year 5% loan of $100, 000. Please...
7. Construct a LOAN AMORTIZATION schedule for a 3 year 5% loan of $100, 000. Please show your calculations clearly and include calculated answers in the table below. (Please only do this question if you are certain how to do it) Amortization Schedule for a Loan of $100 000 Repaid Over 3 Years at 5% Year Payment amount Interest Paid Principal repaid Outstanding loan balance 0 1 2 3
A company’s capital consists of 100 000 ordinary shares issued at $2 and paid to $1...
A company’s capital consists of 100 000 ordinary shares issued at $2 and paid to $1 per share. On 1 September, a first call of 50c was made on the ordinary shares. By 30 September, the call money received amounted to $45 000. No further payments were received, and on 31 October, the shares on which calls were outstanding were forfeited. On 15 November, the forfeited shares were reissued as paid to $1.20 for a payment of $1 per share....
A company's capital consists of 100 000 ordinary shares issued at $2 and paid to $1...
A company's capital consists of 100 000 ordinary shares issued at $2 and paid to $1 per share. On 1 September, a first call of 50c was made on the ordinary shares. By 30 September, the call money received amounted to $45 000. No further payments were received, and on 31 October, the shares on which calls were outstanding were forfeited. On 15 November, the forfeited shares were reissued as paid to $1.50 for a payment of $1 per share....
You are the loan department supervisor for a bank. This installment loan is being paid off...
You are the loan department supervisor for a bank. This installment loan is being paid off early, and it is your task to calculate the rebate fraction, the finance charge rebate (in $), and the payoff for the loan (in $). (Round dollars to the nearest cent.) Amount Financed Number of Payments Monthly Payment Payments Made Rebate Fraction Finance Charge Rebate Loan Payoff $1,700 18 $128.89 13 - $ $
A 20 year loan of $50, 000 is taken out at effective annual interest i =...
A 20 year loan of $50, 000 is taken out at effective annual interest i = 6% for the first 10 years and then i = 7% for the next 10 years. Payments are constant at the end of each year. Find the outstanding balance after the 16th payment.
A 20 year loan of $50, 000 is taken out at effective annual interest i =...
A 20 year loan of $50, 000 is taken out at effective annual interest i = 6% for the first 10 years and then i = 7% for the next 10 years. Payments are constant at the end of each year. Find the outstanding balance after the 16th payment.
3. A loan of $5000 is to be paid off with level payments at the end...
3. A loan of $5000 is to be paid off with level payments at the end of each month at 3% compounded monthly. The amount of interest paid in the 61" payment is $2.24 and the amount of principal repaid in the 42nd payment is $70.31. Find: a) The amount of principal repaid in the 61" payment. b) The size of the level monthly payment. c) The number of months necessary to pay off the loan. d) The amount of...
suppose you paid off a 1200 loan by paying 400 in principal each year plus 10...
suppose you paid off a 1200 loan by paying 400 in principal each year plus 10 percent annual interest over a 3 year period. what is the total payment (interest plus principal) in Year 3
b. An individual obtains a car loan whim pays $30,000. The loan will he paid off...
b. An individual obtains a car loan whim pays $30,000. The loan will he paid off in 3 years, and payments are made monthly. Interest rate on the loan is 7%, and compounding is monthly. 1. Find the amount of monthly payments to pay the loan off. Provide a complete amortization schedule of the loan ( this will entail a long table containing 37 rows). 2. Present your work in detail and explain. Provide references for content. (Excel sheet required).
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT