Question

In: Operations Management

Chen is president of Chen cabinets Inc., a firm that manufactures two types of metal file...

Chen is president of Chen cabinets Inc., a firm that manufactures two types of metal file cabinets.  Chen has a weekly labor capacity of 1,300 hours, with each smaller cabinet taking 1 hour to produce and the larger cabinet requiring 2 hours each. One wooden plank is used for each smaller cabinet and 1.5 planks are used for each larger cabinet.  Chen can get a supply of a maximum of 1000 planks each week.  Each two-drawer model sold yields a $10 profit, and the profit for the larger model is $25.

Chen has the following goals (1). Maximize profit, (2). Maximize number of cabinets produced.

  1. Formulate this Goal programming problem.
  2. Solve the goal programming problem to minimize the maximum % deviation from each goal. Show the solution, target values and % deviation from each goal.
  3. What will be new solution if Goal # 1 was twice as important as Goal # 2?

Solutions

Expert Solution

What if all the resources were consumed for the smaller cabinet, possible production given 1300 hours of labor capacity = 1300/1 = 1300 unit; possible production given 1000 planks = 1000/1 = 1000 units. So, maximum possible production = min(1300, 1000) = 1000

What if all the resources were consumed for the larger cabinet, possible production given 1300 hours of labor capacity = 1300/2 = 650 unit; possible production given 1000 planks = 1000/1.5 = 667 units. So, maximum possible production = min(650, 667) = 650

So, we can take the upper bound of profit as 1000*$10 + 650*$25 = $26,250

Similarly, we can take upper bound for the total number fo cabinets = 1000+650 = 1650

----------------------------------

(a)

Let x1 and x2 be the number of small and large cabinets to be produced. Also, let dj- and dj+ be the under- and over-achievement of the goal-j for j=1,2

Min (p1d1-, p2d2-)

Subject to,

1 x1 + 2 x2 <= 1300 (labor hrs.)

1 x1 + 1.5 x2 <= 1000 (wood)

10 x1 + 25 x2 + d1- - d1+ = 26250 (goal-1)

x1 + x2 + d2- - d2+ = 1650 (goal-2)

x1, x2, dj-, dj+ >= 0 for j=1,2

(b)

We will solve this in a non-preemptive manner i.e. taking all goals at a time with equal weights to their % deviation as follows:

Solver inputs:

Solution:

x1 x2 d1+ d1- d2+ d2-
Value of 100 600 0 10250 0 950
Z2 3.80952E-05 0.000606061 0.966233766
s.t.
Labor 1 2 1300 <= 1300
Wood 1 1.5 1000 <= 1000
Goal-1 10 25 -1 1 26250 = 26250
Goal-2 1 1 -1 1 1650 = 1650

x1 = 100
x2 = 600
Target value for goal-1 = 26250
% deviation from goal-1 = 10250 / 26250 = 39%
Target value for goal-2 = 1650
% deviation from goal-2 = 950 / 1650 = 58%

(c)

Here, we will put twice weight to the first goal's % deviation as follows:

The solver inputs will be the same:

Solution (same as before):

x1 x2 d1+ d1- d2+ d2-
Value of 100 600 0 10250 0 950
Z2 3.80952E-05 0.000606061 0.966233766
s.t.
Labor 1 2 1300 <= 1300
Wood 1 1.5 1000 <= 1000
Goal-1 10 25 -1 1 26250 = 26250
Goal-2 1 1 -1 1 1650 = 1650

x1 = 100
x2 = 600
Target value for goal-1 = 26250
% deviation from goal-1 = 10250 / 26250 = 39%
Target value for goal-2 = 1650
% deviation from goal-2 = 950 / 1650 = 58%


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