In: Economics
The company you are working for is considering replacing an old milling machine. Its current salvage value is estimated to $20,150 and that value will decrease by $3,000 per year. Maintenance costs are expected to be $9,500 this coming year and will likely increase by about $125 per year. A minor overhaul costing an extra $2,250 will be required in year 4.
The company’s MARR is 10%. Determine the Economic Life and EAC* of the old milling machine.
Years | O&M Costs | Overhaul Cost | PV @ 10% | PV Cost @10% | Salvage Value | PV @ 10% | NPV @ 10% |
1 | -9500.00 | 0.90909 | -8636.36 | 20150.00 | 18318.18 | 9681.82 | |
2 | -9625.00 | 0.82645 | -7954.55 | 17150.00 | 14173.55 | 6219.01 | |
3 | -9750.00 | 0.75131 | -7325.32 | 14150.00 | 10631.10 | 3305.79 | |
4 | -9875.00 | -2250.00 | 0.68301 | -6744.76 | 11150.00 | 7615.60 | 870.84 |
5 | -10000.00 | 0.62092 | -6209.21 | 8150.00 | 5060.51 | -1148.70 |
NPV has turned negative in the 5th year which means the value of
economic life lies in between 4th and 5th year.
= 870.84/(870.84+1148.70)
= 0.43
Thus, the economic life is 4.43 years.
Now, the NPV of the cost through its economic lifeis:
=8636.36+7954.55+7325.32+6744.76+6209.21
= 36870.20
Annuity factor for 10% and 4.43 years = 3.444
EAC = 36870.20/3.444
= $10705.63