Convert -99.999 into double precision floating format
show all steps and explanations
In: Computer Science
Convert 103.375 into double precision floating format
show all steps and explanations
In: Computer Science
Convert 103.375 into double precision floating format
show all steps and explanations
In: Computer Science
Convert -99.999 into double precision floating format
show all steps and explanations
In: Computer Science
Search the internet for 5 open source reporting software packages of your choice? Explain why you think these software packages are the best for BI/DSS Reporting? Choose one of them and do associated with the reporting software package. Explain how easy it was for you to use the software?
In: Computer Science
Complete the following task in C++. You may use the following libraries cstdlib, string, iostream.
1 dLL
The class is described according to the simple UML diagram
below:
dLL<T>
-head: item<T>*
-tail: item<T>*
-size: int
----------------------------
+dLL()
+~dLL()
+getHead(): item<T>*
+getTail(): item<T>*
+push(newItem:item<T>*):void
+pop():item<T>*
+getItem(i:int):item<T>*
+minNode():T
+getSize():int
+printList():void
The class variables are as follows:
head: The head pointer of the doubly linked
list.
tail: The tail pointer of the doubly linked
list.
size: The current size of the doubly linked list.
This starts at 0 and increases as the list grows in size.
The class methods are as follows:
dLL: The class constructor. It starts by setting
the variables to null and 0 respectively.
~dLL: The class destructor. It will deallocate all
of the memory in the class.
getHead: This returns the head pointer of the
doubly linked list.
getTail: This returns the tail pointer of the
doubly linked list.
push: This adds a new item to the doubly linked
list, by adding it to the front of the list.
pop: This returns the top item of the linked list.
The item is returned and removed from the list.
getItem: This returns the item of the linked list
at the index specified by the argument but without removing it from
the list. If the index is out of bounds, return null.
minNode: This returns the value of the item that
has the lowest value in the linked list.
getSize: This returns the current size of the
linked list.
printList: This prints out the entire list in
order, from head to tail. Each item's data value is separate by a
comma. For example: 3.1,5,26.6,17.3. Remember to add a newline to
the end of the output.
2. item
The class is described according to the simple UML diagram
below:
item <T>
-data:T
-------------------
+item(t:T)
+~item()
+next: item*
+prev: item*
+getData():T
The class has the following variables:
data: A template variable that stores some piece
of information.
next: A pointer of item type to the next item in
the linked list.
prev: A pointer of item type to the previous item
in the linked list.
The class has the following methods:
item: This constructor receives an argument and
instantiates the data variable with it.
~item: This is the destructor for the item class.
It prints out "Item Deleted" with no quotation marks and a new line
at the end.
getData: This returns the data element stored in
the item.
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Convert -99.999 into double precision floating format
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In: Computer Science
Python Language - Cant seem to get the correct output. Also, need through explanation if possible. much appreciative
XXXXX PYTHON>>>>>>>>> Write a function named shareOneLetter that takes one parameter, wordList a list of words. Create and return a dictionary in which each word in
wordList is a key and the corresponding value is a list of
all the words in wordList that share at least one letter
with that word. There should be no duplicate For example, the following is correct
output: |
In: Computer Science
This laboratory is designed to get you started with the project and random access file I/O.
Class Sdisk { public : Sdisk(string diskname, int numberofblocks, int blocksize); int getblock(int blocknumber, string& buffer); int putblock(int blocknumber, string buffer); int getnumberofblocks(); // accessor function int getblocksize(); // accessor function private : string diskname; // file name of software-disk int numberofblocks; // number of blocks on disk int blocksize; // block size in bytes };
// You can use this to test your Sdisk class int main() { Sdisk disk1("test1",16,32); string block1, block2, block3, block4; for (int i=1; i<=32; i++) block1=block1+"1"; for (int i=1; i<=32; i++) block2=block2+"2"; disk1.putblock(4,block1); disk1.getblock(4,block3); cout << "Should be 32 1s : "; cout << block3 << endl; disk1.putblock(8,block2); disk1.getblock(8,block4); cout << "Should be 32 2s : "; cout << block4 << endl;; }
In: Computer Science
Instructions: Save this file as YourName_PracticeDebuggingTest.
- Part 1 – 4 Debugging Exercises – there are things wrong – either logic or syntax errors. Correct the pseudocode and one Java program. Add the corrected code in BOLD and change the corrected color to RED.
Part 1
Debugging 1: Add the missing code in bold and red.
start
Declarations
num firstNum
num secondNum
string MSG = “Got it!”
housekeeping()
detail()
finish()
stop
housekeeping()
output “Enter three numbers: ”
input firstNum, thirdNum
return
detail()
if ((firstNm + secondNum) = thirdnum) OR
((secondNum + thirdNum) = firstNum)) OR
((firstNum + thirdNum) = secondNum) then
output MSNG
endif
return
finish()
output “End of program”
return
In: Computer Science
Convert 103.375 into double precision floating format
show all steps and explanations
In: Computer Science
- Part 1 – 4 Debugging Exercises – there are things wrong – either logic or syntax errors. Correct the pseudocode and one Java program. Add the corrected code in BOLD and change the corrected color to RED.
Debugging 2: Add the missing code in bold and red.
start
Declarations
num number
housekeeping()
while number >= 15
detailLoop()
endwhile
finish()
stop
housekeeping()
number = 1
return
detailLoop()
output number
num = number + 1
return
finishUp()
output “End of program”
return
In: Computer Science
8.25 Lab 6b Switching Up Months
Objectives
Introduction
In this lab you will continue using the other type of conditional statements: the switch-case.
For switch-case conditional statements, the idea is that you have a variable (the switch) that will determine the next course of action depending on its value (the case).
Example structure would be:
int someVariable = 2; switch (someVariable){ case 1: /*do something*/; break; case 2: /*do something else*/; break; }
someVariable is your swtich and the program will decide a case according to its value.
Assignment
Write the class SwitchingUpMonths.java. This program will be completing exactly the same task as Lab3c, however you will need to use switch-case conditional statements instead of if-else.
That is, your program must:
The sample output for input February:
Enter the month: You entered February Its abbreviation is FEB This is month number 2
In: Computer Science
Adding code that will keep cumulative count of characters?
Hello, I am having issues in figuring out how to keep letter from a .txt file with the declaration of independence, this is my code, I can keep track of the frequency but can't figure out the way to keep adding the total characters, as the you go down the alphabet the number is supposed to be counting up
#define _CRT_SECURE_NO_WARNINGS
#include
#include
#include
#include
#define DEBUG
void main()
{
FILE* fp;
int numChars[26] = {
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 }; //26
characters
unsigned char c;
int ndx;
if ((fp = fopen("DOI.txt", "r")) != NULL)
{
while (1)
{
c =
fgetc(fp);
if
(feof(fp))
{
break;
}
if
(!isalpha(c))
{
continue;
}
ndx =
toupper(c) - 'A';
numChars[ndx]++;
}
printf("Letter\tFrequency\tTotal
Characters\n");
printf("------\t---------\t---------------\n");
for (int i = 0; i < 26;
i++)
{
printf("%c\t%3d\t%d\n", i + 'A', numChars[i]); //Here is where I
should add the counter but can't figure out how to make it
work
}
fclose(fp);
}
else
{
perror("Unable to open
file");
}
getchar();
}
In: Computer Science
In: Computer Science