In: Statistics and Probability
The U.S. Bureau of Labor Statistics released hourly wage figures for various countries for workers in the manufacturing sector. The hourly wage was $30.67 for Switzerland, $20.20 for Japan, and $23.82 for the U.S. Assume that in all three countries, the standard deviation of hourly labor rates is $3.00.
a. Suppose 36 manufacturing workers are selected
randomly from across Switzerland and asked what their hourly wage
is. What is the probability that the sample average will be between
$30.00 and $31.00?
b. Suppose 37 manufacturing workers are selected
randomly from across Japan. What is the probability that the sample
average will exceed $21.00?
c. Suppose 48 manufacturing workers are selected
randomly from across the United States. What is the probability
that the sample average will be less than $22.80?
Answer:
Given that:
The U.S Bureau of labor statistics released hourly wage figures for various countries for workers in the manufacturing sector.
a).Switzerland:
= 30.67, s = 3, n = 36
= p(-1.34 < z < 0.66)
=p(z<0.66) -p(z<1.34)
= 0.7454 - 0.9099
= -0.1645 [p - value from z-table]
b) Japan:
=20.20, s = 3, n = 37
= 1-p(z < 1.63)
=1 - 0.9484
= 0.0516
c) U.S :
=23.82, s = 3, n = 48
= p(z < -2.46)
= 1-0.9931
= 0.0069