Question

The average time spent playing one competitive game in Counter Strike is μ = 50 minutes and standard deviation σ = 7 minutes. I didn’t believe it takes that long so I went ahead and played 100 competitive games for my sample and had an average time of 51 minutes. Use α = 0.05. Can I conclude that the average time spent playing competitive games in Counter Strike is any different that 50 minutes? You can use either Critical Value or P-Value Method, if applicable.

(a) Do the hypothesis test, be sure to write all your work. No work shown or single worded answers will be rewarded minimal to no points. These are some questions to ask yourself if you get stuck. i. What are your hypotheses?, What testing do you have?, What is the test statistic?, What is your conclusion?

(b)Would you expect to get a different conclusion if you did the other method apart from the method you did in part (a)?

(c) Interpret the conclusion, based on the passage.

Answer 1

Here in this scenario the person claim that the average time spent playing one competitive game on counter strike is deffer than 50 min. Here to test this claim we have to use One Sample z Test.

Because here the population standard deviations is known and sample size is large enough. So here using ztest we can conclude at 5% level of significance as below,

The conclusion is given based on z critical value. You can also use p value method. If p<0.05 then Reject null hypothesis.

From the above z test we concluded that the average time spent on competitive game on counter strike is 50 min.

Here is the simple answer.

Thank you.