A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1380 Hz....

A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1380 Hz. The bird-watcher, however, hears a frequency of 1450 Hz. What is the speed of the bird, expressed as a percentage of the speed of sound?

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Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1100 Hz. The bird-watcher, however, hears a frequency of 1130 Hz. What is the speed of the bird, expressed as a percentage of the speed of sound?

Speed of sound in air (v) 343m/s

Source:

Frequency(f_s): 1100 Hz

Velocity(v_s): ?

Stationary:

Frequency(f_l): 1130 Hz

Velocty(v_l): 0 m/s

Applying the Doppler effect:

Since the source is approaching towardsthe listener, the velocity of the source isnegative.

ofspeed of sound in air

genius_generous answered 1 year ago

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