Question

There are several varieties of people who jump off things I wouldn

Answer 1

V_x = 10 * 0.514 m/s = 5.14 m/s

V_x (the velocity in the x direction) is constant assuming drag is negligible. Finding the time it takes the person to hit the water will determine how far they have travelled horizontally.

x-x₀ = v₀*t + 1/2 *a*t²

where x is position, x0 is initial position, v0 is initial velocity, a is acceleration and t is time. If we take the water to be the origin the initial position is 10 feet and acceleration due to gravity is 32.2 ft/s^2 and has to be negative because the diver is falling in the negative direction (towards the origin)

0-10 = 0*t + 1/2 * (-32.2)*t²

t = 0.55727 seconds

D = V*t

Horizontal Distance = Velocity * Time

D = 0.55727 * 5.14 = 2.86 feet

Horizontal distance is 2.86 feet

2. V_x is constant 5.14

V_y = V_y0+a*t

Velocity in the y direction equals initial Y velocity plus acceleration times time. Acceleration is due to gravity (-32.2 ft/s²)

V_y = 0 + (-32.2)*0.55727 = -17.94 feet/second

V_x and V_y are the final directions with the magnitudes already given above. Adding the norm of those two would give the overall velocity magnitude