Question

In: Statistics and Probability

TREND Billed Charge Visit Time (Minutes) $               13,924.00 220 $               &nbs

TREND
Billed Charge Visit Time (Minutes)
$               13,924.00 220
$                  4,956.00 180
$                  8,496.00 165
$               12,036.00 200
$                  4,956.00 173
$               10,384.00 235
$               12,980.00 231
$               10,148.00 215
$                  8,024.00 170
$               12,508.00 295
$               11,328.00 198
$                  9,440.00 145
$               13,452.00 216
$               10,620.00 199
$               10,384.00 240
$                  5,664.00 124
$                  7,316.00 200
$               10,148.00 215
$                  5,900.00 184
$                  7,788.00 165
TREND
Computer the trend for the new visit times in minutes.
Visit Times (min)
300
305
310
320
Now that you have determined the answer, it is time to provide a 1 or 2 sentence
write up of your answer. In statistics, it is important that you not only get the correct
mathematical answer, but that you become comfortable writing up your results in
a manner that is easily understood by the reader/audience.

Solutions

Expert Solution

x y (x-x̅)² (y-ȳ)² (x-x̅)(y-ȳ)
220 13924 462.25 19372321.96 94630.10
180 4956 342.25 20853835.56 84482.10
165 8496 1122.25 1053907.56 34391.10
200 12036 2.25 6317179.56 3770.10
173 4956 650.25 20853835.56 116448.30
235 10384 1332.25 742009.96 31441.10
231 12980 1056.25 11953614.76 112365.50
215 10148 272.25 391125.16 10319.10
170 8024 812.25 2245801.96 42710.10
295 12508 9312.25 8912613.16 288091.10
198 11328 0.25 3259469.16 -902.70
145 9440 2862.25 6822.76 4419.10
216 13452 306.25 15440184.36 68764.50
199 10620 0.25 1204286.76 548.70
240 10384 1722.25 742009.96 35748.10
124 5664 5550.25 14888793.96 287465.70
200 7316 2.25 4869083.56 -3309.90
215 10148 272.25 391125.16 10319.10
184 5900 210.25 13123230.76 52527.70
165 7788 1122.25 3008837.16 58109.10
ΣX ΣY Σ(x-x̅)² Σ(y-ȳ)² Σ(x-x̅)(y-ȳ)
total sum 3970 190452 27413 149630088.8 1332338.00
mean 198.50 9522.60 SSxx SSyy SSxy

sample size ,   n =   20          
here, x̅ = Σx / n=   198.50   ,     ȳ = Σy/n =   9522.60  
                  
SSxx =    Σ(x-x̅)² =    27413.0000          
SSxy=   Σ(x-x̅)(y-ȳ) =   1332338.0          
                  
estimated slope , ß1 = SSxy/SSxx =   1332338.0   /   27413.000   =   48.6024
                  
intercept,   ß0 = y̅-ß1* x̄ =   -124.9794          
                  
so, regression line is   Ŷ =   -124.9794   +   48.6024   *x

......

For x(new visit time) = 300

Y(New billed charge) = -124.9794   +   48.6024   *300 = 14455.75

Similarly we can calculate for others value.

New Visit Time New Billed Charge
300 $14,455.75
305 $14,698.76
310 $14,941.77
320 $15,427.79

We have first created the relationship/equation between two variable(dependent and independent) using trend/regression analysis. Using that trend equation we have predicted the dependent variable based on independent variable.


Related Solutions

Billed Charge Visit Time (Minutes) $           13,924.00 220 $             4,956.00 180 $       &n
Billed Charge Visit Time (Minutes) $           13,924.00 220 $             4,956.00 180 $             8,496.00 165 $           12,036.00 200 $             4,956.00 173 $           10,384.00 235 $           12,980.00 231 $           10,148.00 215 $             8,024.00 170 $           12,508.00 295 $           11,328.00 198 $             9,440.00 145 $           13,452.00 216 $           10,620.00 199 $           10,384.00 240 $             5,664.00 124 $             7,316.00 200 $           10,148.00 215 $             5,900.00 184 $             7,788.00 165 SLOPE Now that you have determined the answer, it is time to provide a 1...
INTERCEPT Billed Charge Visit Time (Minutes) $           13,924.00 220 $             4,956.00 180 $ &nb
INTERCEPT Billed Charge Visit Time (Minutes) $           13,924.00 220 $             4,956.00 180 $             8,496.00 165 $           12,036.00 200 $             4,956.00 173 $           10,384.00 235 $           12,980.00 231 $           10,148.00 215 $             8,024.00 170 $           12,508.00 295 $           11,328.00 198 $             9,440.00 145 $           13,452.00 216 $           10,620.00 199 $           10,384.00 240 $             5,664.00 124 $             7,316.00 200 $           10,148.00 215 $             5,900.00 184 $             7,788.00 165 INTERCEPT Now that you have determined the answer, it is time to provide a...
A study showed that in a certain month, the mean time spent per visit to Facebook was 19.5 minutes.
  1.       A study showed that in a certain month, the mean time spent per visit to Facebook was 19.5 minutes. Assumes the standard deviation of the population is 8 minutes. Suppose that a simple random sample of 100 visits in that month has a sample mean of 21.52 minutes. A social scientist is interested in knowing whether the mean time of Facebook visits has increased. Perform the hypothesis test and compute the P-value. Based on the P value, what...
Visit the Meeting calendars, statements, and minutes section of the U.S. Federal Reserve Federal Open Market...
Visit the Meeting calendars, statements, and minutes section of the U.S. Federal Reserve Federal Open Market Committee. If this page does not load, type "FOMC meetings" in the "Search" box located on the U.S. Federal Reserve home page. Next, select a date from any year and click on the “Statement” link. Respond to the following questions by writing 1-2 paragraphs for each item: What action did the Committee take on this date? What comments (if any) were made with respect...
The wait time (after a scheduled arrival time) in minutes for a train to arrive is...
The wait time (after a scheduled arrival time) in minutes for a train to arrive is Uniformly distributed over the interval [0,12]. You observe the wait time for the next 95 trains to arrive. Assume wait times are independent. Part a) What is the approximate probability (to 2 decimal places) that the sum of the 95 wait times you observed is between 536 and 637? Part b) What is the approximate probability (to 2 decimal places) that the average of...
The average number of minutes Americans commute to work is 27.7 minutes. The average commute time...
The average number of minutes Americans commute to work is 27.7 minutes. The average commute time in minutes for 48 cities are as follows. Albuquerque 23.6 Jacksonville 26.5 Phoenix 28.6 Atlanta 28.6 Kansas City 23.7 Pittsburgh 25.3 Austin 24.9 Las Vegas 28.7 Portland 26.7 Baltimore 32.4 Little Rock 20.4 Providence 23.9 Boston 32.0 Los Angeles 32.5 Richmond 23.7 Charlotte 26.1 Louisville 21.7 Sacramento 26.1 Chicago 38.4 Memphis 24.1 Salt Lake City 20.5 Cincinnati 25.2 Miami 31.0 San Antonio 26.4 Cleveland...
Hospital Size Time to Defibrillation < or equal to 2 minutes >2 minutes Small (<250 beds)...
Hospital Size Time to Defibrillation < or equal to 2 minutes >2 minutes Small (<250 beds) 1124    576 medium (250-499 beds) 2178 886 Large (>500 beds) 1387    565 One research question that could be posed using the available data: " is there an advantage to being at a larger hospital for patients suffering cardiac arrest?" Determine a method that would be appropriate for answering this research questions. Using Statcrunch and the available data, perform the statistical procedure deemed...
Surf the web for at least 15 minutes. Visit at least two different e-commerce sites. Make...
Surf the web for at least 15 minutes. Visit at least two different e-commerce sites. Make a list describing in detail all the different marketing communication tools you see being used. Which do you believe is the most effective and why?
A manager wishes to see if the time (in minutes) it takes for their workers to...
A manager wishes to see if the time (in minutes) it takes for their workers to complete a certain task will change when they are allowed to wear ear buds at work. A random sample of 25 workers' times were collected before and after. Test the claim that the time to complete the task has changed at a significance level of α=0.10. For the context of this problem, μd=μafter−μbefore where the first data set represents after and the second data...
A manager wishes to see if the time (in minutes) it takes for their workers to...
A manager wishes to see if the time (in minutes) it takes for their workers to complete a certain task will decrease when they are allowed to wear ear buds at work. A random sample of 10 workers' times were collected before and after wearing ear buds. Assume the data is normally distributed. Perform a Matched-Pairs hypothesis test for the claim that the time to complete the task has decreased at a significance level of α=0.01α=0.01. If you wish to...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT