Question

+1 nc is placed at the origin and -1 nc is placed on the x-axis 1 meter away. Find the total Electric field in components form and magnitude angle form for points given P1 = (0,1) namely the point with coordinate x = 0 y = 1 P2 = (0.5, 1) P3 = (1,1) P4 = (1.5, 1)

Answer 1

(1) charge Q1 = + 1 nC;

charge Q2 = -1 nC;

(a) Distance between point P(0,1) and charge Q1 is R1;

Distance between point P(0,1) and charge Q2 is R2;

angle A = 45 degrees;

electric field at point P due to charge Q1 in vector form;

electric field at point P due to charge Q2 in vector form;

net electric field at point P;

Substitute all the constants;

direction of net electric field;

(b) Distance between point P(0.5,1) and charge Q1 is R1;

Distance between point P(0.5,1) and charge Q2 is R2;

angle A = 53.13 degrees; and angle B = 63.43 degrees

electric field at point P due to charge Q1 in vector form;

electric field at point P due to charge Q2 in vector form;

net electric field at point P;

direction of net electric field;

(c) Distance between point P(1,1) and charge Q1 is R1;

Distance between point P(1,1) and charge Q2 is R2;

angle A = 45 degrees;

electric field at point P due to charge Q1 in vector form;

electric field at point P due to charge Q2 in vector form;

net electric field at point P;

direction of net electric field;

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