An object with a density of 761.0 kg/m3 and a mass of 1399.0 kg is thrown...

An object with a density of 761.0 kg/m³ and a mass of 1399.0 kg is thrown into the ocean. Find the volume that sticks out of the water. (use ?_seawater = 1024 kg/m³)

Expert Solution

From Archimedes Principle, weight of water displaced by floating object is equal to weight of object.

volume of water displaced = part below water line

= 1399x9.8 m/s^2/1024 x 9.8 m/s^2
= 1.366 m^3

Volume of Whole object = Mass/Density

= 1399/761 = 1.83837 m^3

Volume above waterline = 1.83837 m^3 - 1.366 m^3 = 0.47237 m^3 = 0.472 m^3 (nearly)

genius_generous answered 3 hours ago

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