A physicist at a fireworks display times the lag between seeing an explosion and hearing its...

A physicist at a fireworks display times the lag between seeing an explosion and hearing its sound, and finds it to be 0.300 s. (Enter your answers to at least four decimal places. Use the following relationship between Kelvin and Celsius:

T(K) = T(°C) + 273.15

(a)

How far away (in m) is the explosion if air temperature is 22.0°C and if you neglect the time taken for light to reach the physicist?

103.2215 m ( I know this is correct)

(b)

Calculate the distance to the explosion (in m) taking the speed of light into account. Note that this distance is negligibly greater.

103.2211 is wrong and I am not sure why

Expert Solution

(a) Speed of sound at 22 C is given as v = 344.31 m/s

distance = speed*time

= 344.31*0.3

= 103.293 m

(b) time taken by light is

time taken by sound

time difference

genius_generous answered 2 years ago

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A physicist at a fireworks display times the lag between seeing an explosion and hearing its...

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