In: Statistics and Probability
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. A random sample of 5340 permanent dwellings on an entire reservation showed that 1634 were traditional hogans.
(a) Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.)
(b) Find a 99% confidence interval for p. (Round your answer to three decimal places.)
lower limit
upper limit
Give a brief interpretation of the confidence interval. 99% of all confidence intervals would include the true proportion of traditional hogans. 99% of the confidence intervals created using this method would include the true proportion of traditional hogans. 1% of all confidence intervals would include the true proportion of traditional hogans. 1% of the confidence intervals created using this method would include the true proportion of traditional hogans.
(c) Do you think that np > 5 and nq > 5 are satisfied for this problem? Explain why this would be an important consideration
. Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately binomial. No, the conditions are not satisfied. This is important because it allows us to say that p̂ is approximately binomial. No, the conditions are not satisfied. This is important because it allows us to say that p̂ is approximately normal. Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately normal.
Answer a)
Point estimate of p = Sample proportion = 1634/5340
Point estimate of p = 0.3060
Answer b)
Lower Limit: 0.290
Upper Limit: 0.322
Interpretation
99% of all confidence intervals would include the true proportion of traditional hogans.
Answer c)
n = 5340 and p = 0.306
n*p = 5340*0.306 = 1634 > 5
n*(1-p) = 5340*(1-0.306) = 3706 > 5
Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately normal.