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I have 2 questions: Assuming 100% dissociation, calculate the freezing point and boiling point of 2.73...

I have 2 questions:

Assuming 100% dissociation, calculate the freezing point and boiling point of 2.73 m K3PO4(aq). Constants may be found here.

T(f)=

T(b)=

A solution is made by dissolving 0.558 mol of nonelectrolyte solute in 793 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants may be found here.

T(f)=

T(b)=

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Expert Solution

queen_honey_blossom answered 2 years ago
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