Question
In: Statistics and Probability
Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals...
Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean ALT levels for the individuals who do not drink alcohol is 32 with a standard deviation of 14, and 37 individuals were in the sample. The mean ALT levels for individuals who drink alcohol is 69 with a standard deviation of 19, and 38 individuals were in the sample. Construct and interpret a 95% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol.
Solutions
Expert Solution
Solution-
Let X1 =individuals who drink alcohol.
X2 =Individuals who do not drink alcohol
orchestra answered 2 years agoRelated Solutions
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