Question

In: Statistics and Probability

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 140 use humor, while a random sample of 500 television ads in the United States reveals that 128 use humor. (a) Set up the null and alternative hypotheses needed to determine whether the proportion of ads using humor in the United Kingdom differs from the proportion of ads using humor in the United States. H0: p1 − p2 0 versus Ha: p1 − p2 0. (b) Test the hypotheses you set up in part a by using critical values and by setting α equal to .10, .05, .01, and .001. How much evidence is there that the proportions of U.K. and U.S. ads using humor are different? (Round the proportion values to 3 decimal places. Round your answer to 2 decimal places.) z H0 at each value of α; evidence. (c) Set up the hypotheses needed to attempt to establish that the difference between the proportions of U.K. and U.S. ads using humor is more than .05 (five percentage points). Test these hypotheses by using a p-value and by setting α equal to .10, .05, .01, and .001. How much evidence is there that the difference between the proportions exceeds .05? (Round the proportion values to 3 decimal places. Round your z value to 2 decimal places and p-value to 4 decimal places.) z p-value H0 at each value of α = .10 and α = .05; evidence. (d) Calculate a 95 percent confidence interval for the difference between the proportion of U.K. ads using humor and the proportion of U.S. ads using humor. Interpret this interval. Can we be 95 percent confident that the proportion of U.K. ads using humor is greater than the proportion of U.S. ads using humor? (Round the proportion values to 3 decimal places. Round your answers to 4 decimal places.) 95% of Confidence Interval [ , ] the entire interval is above zero.

Solutions

Expert Solution

(a) Set up the null and alternative hypotheses needed to determine whether the proportion of ads using humor in the United Kingdom differs from the proportion of ads using humor in the United States.

The hypothesis being tested is:

H0: p1 = p2

Ha: p1 ≠ p2

(b) Test the hypotheses you set up in part a by using critical values and by setting α equal to .10, .05, .01, and .001. How much evidence is there that the proportions of U.K. and U.S. ads using humor are different? (Round the proportion values to 3 decimal places. Round your answer to 2 decimal places.)

p1 p2 pc
0.35 0.256 0.2978 p (as decimal)
140/400 128/500 268/900 p (as fraction)
140. 128. 268. X
400 500 900 n
0.094 difference
0. hypothesized difference
0.0307 std. error
3.06 z
.0022 p-value (two-tailed)
α z-critical Decision when z = 3.06
0.001 3.29 Fail to reject Ho
0.01 2.575 Reject Ho
0.05 1.96 Reject Ho
0.1 1.645 Reject Ho

(c) Set up the hypotheses needed to attempt to establish that the difference between the proportions of U.K. and U.S. ads using humor is more than .05 (five percentage points). Test these hypotheses by using a p-value and by setting α equal to .10, .05, .01, and .001. How much evidence is there that the difference between the proportions exceeds .05? (Round the proportion values to 3 decimal places. Round your z value to 2 decimal places and p-value to 4 decimal places.)

The hypothesis being tested is:

H0: p1 - p2 0.05

Ha: p1 - p2 < 0.05

p1 p2
0.35 0.256 p (as decimal)
140/400 128/500 p (as fraction)
140. 128. X
400 500 n
0.094 difference
0.05 hypothesized difference
0.0308 std. error
1.43 z
.0767 p-value (one-tailed, upper)
α z-critical Decision when z = 1.43
0.001 3.29 Fail to reject Ho
0.01 2.575 Fail to reject Ho
0.05 1.96 Fail to reject Ho
0.1 1.645 Reject Ho

(d) Calculate a 95 percent confidence interval for the difference between the proportion of U.K. ads using humor and the proportion of U.S. ads using humor. Interpret this interval. Can we be 95 percent confident that the proportion of U.K. ads using humor is greater than the proportion of U.S. ads using humor? (Round the proportion values to 3 decimal places. Round your answers to 4 decimal places.)

0.0336 confidence interval 95.% lower
0.1544 confidence interval 95.% upper
0.0604 margin of error

Related Solutions

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 146 use humor, while a random sample of 500 television ads in the United States reveals that 124 use humor. (b) Test the hypotheses you...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 142 use humor, while a random sample of 500 television ads in the United States reveals that 126 use humor. (a) Set up the null...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 140 use humor, while a random sample of 500 television ads in the United States reveals that 128 use humor. (a) Set up the null...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 450 television ads in the United Kingdom reveals that 137 of them use humor, while a random sample of 520 television ads in the United States reveals that 175 of them use humor. (a)...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 450 television ads in the United Kingdom reveals that 137 of them use humor, while a random sample of 520 television ads in the United States reveals that 175 of them use humor. (a)...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 142 use humor, while a random sample of 500 television ads in the United States reveals that 123 use humor. (a) Set up the null...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 145 use humor, while a random sample of 500 television ads in the United States reveals that 124 use humor. (a) Set up the null...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 143 use humor, while a random sample of 500 television ads in the United States reveals that 126 use humor. (a) Set up the null...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor. (a) Suppose that a random sample of 387 television ads in the United Kingdom reveals that 130 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 145 use humor, while a random sample of 500 television ads in the United States reveals that 124 use humor. (a) Set up the null...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT