In: Statistics and Probability
In a survey, 30 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $32 and standard deviation of $10. Find the margin of error at a 90% confidence level.m
Given, mean(x) = $32, standard deviation() = $10, sample size(n) = 30 and level of significance () = 10%
where is standard normal variate. So,
margin of error =
= =
The margin of error is 3.003078 at 90% confidence level.
We also calculated margin of error with the help of R software.