Question

In: Statistics and Probability

1) Run a regression model to estimate the cost of a building using average storey height...

1) Run a regression model to estimate the cost of a building using average storey height (mean centered) and total floor area (mean centered)

2) Run a regression model to estimate the cost of a building using average storey height (mean centered), total floor area (mean centered), and the type of construction (dummy coded with reinforced concrete as the control group)

Interpret the slopes, intercepts, and regression statistics in the models

Building type Average floor area (m2) Total floor area (m2) avg story height(cms) COST (HK$)
1 1852 81478 410 1467000000
1 1608 64313 411 1150000000
1 1430 55783 403 1028000000
1 1562 57794 390 1100000000
1 1109 37695 391 728000000
1 905 28048 382 558000000
1 1852 81478 410 1467000000
1 901 30617 391 631000000
1 1727 69062 400 1223000000
1 1161 37148 394 761000000
1 1004 37141 400 713000000
1 1216 38912 390 784000000
1 2007 88302 422 1593000000
1 2983 173000 440 2649000000
2 1523 70080 372 1210000000
2 912 28286 370 607000000
2 1343 53715 382 977000000
2 1175 32908 381 700000000
2 1203 40902 393 811000000
2 1393 52951 392 1001000000
2 713 20681 375 468000000
2 1047 37681 411 747000000
2 1506 63270 421 1156000000
2 1642 70624 423 1268000000
2 1848 73936 403 1333000000
2 1627 60190 402 1162000000
2 1301 40321 384 864000000
2 905 25330 405 561000000
2 1727 72514 400 1303000000
2 1414 52318 392 1013000000
2 2001 76022 431 1487000000
2 400 9200 380 263000000
2 3100 102190 454 2112000000
2 1677 83860 410 1519000000
2 2415 130032 420 2045000000
2 1555 46637 410 1025000000
2 792 20596 420 540000000
Building Type
1 Reinforced Concrete
2 Steel

Solutions

Expert Solution

At first I use regression analysis in excel to show the cost of the building depending upon avg storey of building & total floor cost of two type of building.

So y = alpha + beta1 total floor area + beta2 avg storey building + error

Please look at the SPSS output below :-

In the above output model summary table shows the R-square value. That defines goodness of the fit of the model. Higher the value of R^2 higher is the goodness of fit. Here Rsquare = .98 means 98% of the model is defined by the two independent variables and rest 2% by the error.

Now our null hypothesis is H0 : alpha = 0 = beta

alternative Ha : alpha 0 beta

By seeing the p-value at co-efficient table we can say that p value for the constant that is alpha and avg. storey building that beta1 are less than 0.05 at 95% confidence interval & also less than 0.05 in case of total floor area that coefficient of total floor area beta2. so null hypothesis is rejected in case of constant & beta1 beta2. This model is good & significancde to the test. We can have better rsquare value also.So, we perform an another model where we only consider the building type 1.

Please look at the below output of SPSS :-

Here R square is .992. That is 99.2% of the model is derived by the two independent variable. Now p value of alpha , beta1 are greater than 0.05 & less than 0.05 for beta2. so we cannot reject null hypothesis for alpha & beta1 , which is a contradictory result. But here Rsquare value is more so we could have better fit of the model in this case but all the parameters are not significant to the test.


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