Question

In: Statistics and Probability

Run the R command y <- rchisq(1000,2). Then use your exploratory tools to identify which, if...

Run the R command y <- rchisq(1000,2). Then use your exploratory tools to identify which, if any of the following are correct. THERE ARE more than one correct answer.

Group of answer choices:

The distribution is unimodal.

The mean would be an appropriate measure of location.

The median would be an appropriate measure of location

The distribution is skewed to the right

The standard deviation would be an appropriate measure of spread.

Solutions

Expert Solution

solution:

Sol:

y <- rchisq(1000,2)

y

hist(y)

mean(y)

median(y)

boxplot(y)

mean for data is 1.981126

median=1.380834

mean>median

skewed to right

From

boxplot we could see outliers

median would be appropriate measure of centre

Rscreensht

median would be an appropriate measure of location

The distribution is sewed to right

please give me thumb up

orchestra answered 2 years ago
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